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1. Write an equation in standard form of an ellipse that has a vertex at [tex]\((0, 6)\)[/tex], a co-vertex at [tex]\((1, 0)\)[/tex], and a center at the origin.

A. [tex]\[ x^2 + \frac{y^2}{6} = 1 \][/tex]

B. [tex]\[ \frac{x^2}{36} + \frac{y^2}{2} = 1 \][/tex]

C. [tex]\[ \frac{x^2}{36} + y^2 = 1 \][/tex]

D. [tex]\[ x^2 + \frac{y^2}{36} = 1 \][/tex]


Sagot :

To find the standard form of the equation of an ellipse that has a vertex at (0,6), a co-vertex at (1,0), and a center at the origin (0,0), follow these steps:

1. Identify the values of [tex]\(a\)[/tex] and [tex]\(b\)[/tex]:
- The vertex (0,6) indicates that the distance from the center to a vertex along the y-axis is [tex]\(a = 6\)[/tex].
- The co-vertex (1,0) indicates that the distance from the center to a co-vertex along the x-axis is [tex]\(b = 1\)[/tex].

2. Calculate [tex]\(a^2\)[/tex] and [tex]\(b^2\)[/tex]:
- [tex]\(a^2 = 6^2 = 36\)[/tex]
- [tex]\(b^2 = 1^2 = 1\)[/tex]

3. Write the standard form of the ellipse:
- For an ellipse with a vertical major axis centered at the origin, the standard form of the equation is:
[tex]\[ \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 \][/tex]

4. Plug the values of [tex]\(a^2\)[/tex] and [tex]\(b^2\)[/tex] into the equation:
- Substituting [tex]\(a^2 = 36\)[/tex] and [tex]\(b^2 = 1\)[/tex], the equation becomes:
[tex]\[ \frac{x^2}{1} + \frac{y^2}{36} = 1 \][/tex]

So, the correct equation in standard form is:
[tex]\[ \boxed{\frac{x^2}{1} + \frac{y^2}{36} = 1} \][/tex]
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