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1. [tex]$CH _4 + 2 O _2 \longrightarrow CO _2 + H _2 O$[/tex]
2. [tex]$4 Fe + 3 O _2 \longrightarrow 2 Fe _2 O _3$[/tex]
3. [tex]$Mg + 2 HCl \longrightarrow MgCl _2 + H _2$[/tex]
4. [tex]$Fe _2 O _3 + H _2 O \longrightarrow Fe ( OH )_3$[/tex]
5. [tex]$NaOH + CuCl _2 \longrightarrow Cu ( OH )_2 + NaCl$[/tex]
6. [tex]$Cu + HNO _3 \longrightarrow Cu \left( NO _3 \right)_2 + H _2 O + NO _2$[/tex]
7. [tex]$C _6 H _{12} + O _2 \longrightarrow CO _2 + H _2 O$[/tex]
8. [tex]$Hg + H _2 SO _4 \longrightarrow HgSO _4 + H _2 O + SO _2$[/tex]
9. [tex]$Al + H _2 SO _4 \longrightarrow Al _2\left( SO _4 \right)_3 + H _2$[/tex]
10. [tex]$ZnS + O _2 \longrightarrow ZnO + SO _2$[/tex]
11. [tex]$HCl + MnO _2 \longrightarrow MnCl _2 + H _2 O + Cl _2$[/tex]
12. [tex]$KClO _3 \longrightarrow KCl + O _2$[/tex]

Sagot :

GinnyAnsweridn
Certainly! I'll provide a detailed step-by-step solution for balancing each of these chemical equations.

1. CH₄ + 2 O₂ → CO₂ + 2 H₂O
- Carbon (C): 1 atom on both sides (balanced).
- Hydrogen (H): 4 atoms on both sides (balanced).
- Oxygen (O): 4 atoms on both sides (balanced).

2. 4 Fe + 3 O₂ → 2 Fe₂O₃
- Iron (Fe): 4 atoms on both sides (balanced).
- Oxygen (O): 6 atoms on both sides (balanced).

3. Mg + 2 HCl → MgCl₂ + H₂
- Magnesium (Mg): 1 atom on both sides (balanced).
- Hydrogen (H): 2 atoms on both sides (balanced).
- Chlorine (Cl): 2 atoms on both sides (balanced).

4. Fe₂O₃ + 3 H₂O → 2 Fe(OH)₃
- Iron (Fe): 2 atoms on both sides (balanced).
- Oxygen (O): 6 atoms on both sides (balanced).
- Hydrogen (H): 6 atoms on both sides (balanced).

5. 2 NaOH + CuCl₂ → Cu(OH)₂ + 2 NaCl
- Sodium (Na): 2 atoms on both sides (balanced).
- Hydrogen (H): 2 atoms on both sides (balanced).
- Oxygen (O): 2 atoms on both sides (balanced).
- Copper (Cu): 1 atom on both sides (balanced).
- Chlorine (Cl): 2 atoms on both sides (balanced).

6. Cu + 4 HNO₃ → Cu(NO₃)₂ + 2 H₂O + 2 NO₂
- Copper (Cu): 1 atom on both sides (balanced).
- Hydrogen (H): 4 atoms on both sides (balanced).
- Nitrogen (N): 4 atoms on both sides (balanced).
- Oxygen (O): 12 atoms on both sides (balanced).

7. C₆H₁₂ + 9 O₂ → 6 CO₂ + 6 H₂O
- Carbon (C): 6 atoms on both sides (balanced).
- Hydrogen (H): 12 atoms on both sides (balanced).
- Oxygen (O): 18 atoms on both sides (balanced).

8. Hg + 2 H₂SO₄ → HgSO₄ + 2 H₂O + SO₂
- Mercury (Hg): 1 atom on both sides (balanced).
- Hydrogen (H): 4 atoms on both sides (balanced).
- Sulfur (S): 2 atoms on both sides (balanced).
- Oxygen (O): 8 atoms on both sides (balanced).

9. 2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
- Aluminum (Al): 2 atoms on both sides (balanced).
- Hydrogen (H): 6 atoms on both sides (balanced).
- Sulfur (S): 3 atoms on both sides (balanced).
- Oxygen (O): 12 atoms on both sides (balanced).

10. 2 ZnS + 3 O₂ → 2 ZnO + 2 SO₂
- Zinc (Zn): 2 atoms on both sides (balanced).
- Sulfur (S): 2 atoms on both sides (balanced).
- Oxygen (O): 6 atoms on both sides (balanced).

11. 4 HCl + MnO₂ → MnCl₂ + 2 H₂O + Cl₂
- Hydrogen (H): 4 atoms on both sides (balanced).
- Chlorine (Cl): 4 atoms on both sides (balanced).
- Manganese (Mn): 1 atom on both sides (balanced).
- Oxygen (O): 2 atoms on both sides (balanced).

12. 2 KClO₃ → 2 KCl + 3 O₂
- Potassium (K): 2 atoms on both sides (balanced).
- Chlorine (Cl): 2 atoms on both sides (balanced).
- Oxygen (O): 6 atoms on both sides (balanced).

These are the balanced equations for each reaction, ensuring that the number of atoms of each element is equal on both sides of the equation.
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