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Solve for [tex]\( x \)[/tex].

[tex]\[ 3x = 6x - 2 \][/tex]

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[tex]\[
\begin{aligned}
a_1 &= 4(1) + 2 \\
&= 4 + 2 \\
&= 6
\end{aligned}
\][/tex]
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Response:

[tex]\[
\begin{aligned}
a_1 &= 4(1) + 2 \\
&= 4 + 2 \\
&= 6
\end{aligned}
\][/tex]


Sagot :

Sure, let's solve the problem step-by-step.

We start with the given equation:
[tex]\[ a1 = 4(1) + 2 \][/tex]

First, perform the multiplication:
[tex]\[ 4 \times 1 = 4 \][/tex]

Next, add the result of the multiplication to 2:
[tex]\[ 4 + 2 = 6 \][/tex]

So, the final value of [tex]\( a1 \)[/tex] is:
[tex]\[ a1 = 6 \][/tex]

Therefore, [tex]\( a1 = 6 \)[/tex].