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The temperature, [tex]\( t \)[/tex], in degrees Fahrenheit, can be found by counting the number of cricket chirps, [tex]\( c \)[/tex], heard in 14 seconds and then adding 40. The equation [tex]\( t = c + 40 \)[/tex] models the relationship between the temperature and the number of cricket chirps.

What is true about the graph that represents this real-world scenario? Select two options.

A. The graph is continuous.
B. All values of [tex]\( t \)[/tex] must be positive.
C. A viable solution is [tex]\((-2, 38)\)[/tex].
D. A viable solution is [tex]\((0.5, 40.5)\)[/tex].
E. A viable solution is [tex]\((10, 50)\)[/tex].


Sagot :

Let's analyze the given model [tex]\( t = c + 40 \)[/tex] and determine the correctness of each statement in the context provided.

### Viable Solutions:
We need to confirm if the given points are viable solutions by substituting [tex]\( c \)[/tex] into the equation [tex]\( t = c + 40 \)[/tex].

1. A viable solution is [tex]\((10, 50)\)[/tex]:
- For [tex]\( c = 10 \)[/tex]:
[tex]\[ t = 10 + 40 = 50 \][/tex]
- This point satisfies the equation, making [tex]\((10, 50)\)[/tex] a viable solution.

2. A viable solution is [tex]\((0.5, 40.5)\)[/tex]:
- For [tex]\( c = 0.5 \)[/tex]:
[tex]\[ t = 0.5 + 40 = 40.5 \][/tex]
- This point satisfies the equation, making [tex]\((0.5, 40.5)\)[/tex] a viable solution.

3. A viable solution is [tex]\((-2, 38)\)[/tex]:
- For [tex]\( c = -2 \)[/tex]:
[tex]\[ t = -2 + 40 = 38 \][/tex]
- Although the point satisfies the equation mathematically, [tex]\( c \)[/tex] representing the number of cricket chirps cannot be negative. Thus, [tex]\((-2, 38)\)[/tex] is not a viable solution in the real-world context.

### Graph Characteristics:
Next, we examine the properties of the graph representing the equation [tex]\( t = c + 40 \)[/tex]:

1. The graph is continuous:
- Both [tex]\( c \)[/tex] and [tex]\( t \)[/tex] are essentially continuous variables in real-world observations (even though [tex]\( c \)[/tex] would typically be an integer in counts), and therefore, the graph representing this equation would be continuous.

2. All values of [tex]\( t \)[/tex] must be positive:
- This is not necessarily true since if [tex]\( c \)[/tex] is negative (which theoretically could happen if considering the mathematical domain without physical constraints), [tex]\( t \)[/tex] could be less than 40, potentially negative. However, chirps, [tex]\( c \)[/tex], in real life should be non-negative, implying a minimum temperature of 40. Still, as per the strict mathematical interpretation, this statement is not universally true.

### Summary:
Based on the analysis, the two correct statements about the graph that represents this real-world scenario are:

1. The graph is continuous.
2. A viable solution is [tex]\((0.5, 40.5)\)[/tex].
3. A viable solution is [tex]\( (10, 50) \)[/tex].

Thus, the selected options are:

- The graph is continuous.
- A viable solution is [tex]\((0.5, 40.5)\)[/tex].
- A viable solution is [tex]\((10, 50)\)[/tex].

As we're asked to select two, the two viable and correct options to be highlighted would be:

- The graph is continuous.
- A viable solution is [tex]\((10, 50)\)[/tex].

Or alternately, noting the solution's nature, these combinations can work:

- The graph is continuous.
- A viable solution is [tex]\((0.5, 40.5)\)[/tex].

Either combination correctly identifies true aspects of the graph and the provided model.
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