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The table shows the results of a student survey done by the chef at a school cafeteria. What is the probability that one of these students is female and likes peas?

\begin{tabular}{|l|c|c|c|}
\hline & Likes peas & Dislikes peas & Total \\
\hline Male & 58 & 42 & 100 \\
\hline Female & 64 & 36 & 100 \\
\hline Total & 122 & 78 & 200 \\
\hline
\end{tabular}

A. [tex]$36\%$[/tex]

B. [tex]$32\%$[/tex]

C. [tex]$18\%$[/tex]

D. [tex]$64\%$[/tex]


Sagot :

Let's solve this step-by-step:

1. Identify the relevant numbers from the survey table:
- The number of female students who like peas is 64.
- The total number of students surveyed is 200.

2. Calculate the probability that a randomly selected student is female and likes peas:
- Probability is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
- The favorable outcome here is being female and liking peas, which is 64.
- The total number of possible outcomes is the total number of students, which is 200.

3. Find the probability in terms of percentage:
- The probability [tex]\( P \)[/tex] can be calculated as:
[tex]\[ P = \frac{\text{Number of females who like peas}}{\text{Total number of students}} \times 100\% \][/tex]
- Plugging in the numbers, we get:
[tex]\[ P = \frac{64}{200} \times 100\% \][/tex]

4. Perform the division and multiplication to find the exact percentage:
- First, perform the division:
[tex]\[ \frac{64}{200} = 0.32 \][/tex]
- Then, multiply by 100 to convert to a percentage:
[tex]\[ 0.32 \times 100\% = 32\% \][/tex]

Thus, the probability that a randomly selected student is female and likes peas is [tex]\( 32\% \)[/tex].

Therefore, the correct answer is:
B. [tex]\(32\%\)[/tex]
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