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Which ordered pair is a solution to the following linear inequality?

[tex]\[ y \ \textless \ x + 1 \][/tex]

A. [tex]\((-4, -1)\)[/tex]

B. [tex]\((-2, 4)\)[/tex]

C. [tex]\((1, -2)\)[/tex]

D. [tex]\((-3, 0)\)[/tex]


Sagot :

To determine which ordered pairs satisfy the inequality [tex]\(y < x + 1\)[/tex], let's evaluate each of the given pairs.

1. Consider the pair [tex]\((-4, -1)\)[/tex]:
- Substitute [tex]\(x = -4\)[/tex] and [tex]\(y = -1\)[/tex] into the inequality:
[tex]\[ y < x + 1 \implies -1 < -4 + 1 \][/tex]
- Simplify the right side:
[tex]\[ -1 < -3 \][/tex]
- This inequality is not true because [tex]\(-1\)[/tex] is not less than [tex]\(-3\)[/tex].

2. Consider the pair [tex]\((-2, 4)\)[/tex]:
- Substitute [tex]\(x = -2\)[/tex] and [tex]\(y = 4\)[/tex] into the inequality:
[tex]\[ y < x + 1 \implies 4 < -2 + 1 \][/tex]
- Simplify the right side:
[tex]\[ 4 < -1 \][/tex]
- This inequality is not true because [tex]\(4\)[/tex] is not less than [tex]\(-1\)[/tex].

3. Consider the pair [tex]\((1, -2)\)[/tex]:
- Substitute [tex]\(x = 1\)[/tex] and [tex]\(y = -2\)[/tex] into the inequality:
[tex]\[ y < x + 1 \implies -2 < 1 + 1 \][/tex]
- Simplify the right side:
[tex]\[ -2 < 2 \][/tex]
- This inequality is true because [tex]\(-2\)[/tex] is less than [tex]\(2\)[/tex].

4. Consider the pair [tex]\((-3, 0)\)[/tex]:
- Substitute [tex]\(x = -3\)[/tex] and [tex]\(y = 0\)[/tex] into the inequality:
[tex]\[ y < x + 1 \implies 0 < -3 + 1 \][/tex]
- Simplify the right side:
[tex]\[ 0 < -2 \][/tex]
- This inequality is not true because [tex]\(0\)[/tex] is not less than [tex]\(-2\)[/tex].

From our evaluation, the ordered pair [tex]\((1, -2)\)[/tex] is the only pair that satisfies the inequality [tex]\(y < x + 1\)[/tex]. Therefore, the solution is:

[tex]\((1, -2)\)[/tex].