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Sagot :
To divide the expression [tex]\((-8a + 16) \div (a - 2)\)[/tex], follow these steps:
1. Identify the numerator and the denominator:
[tex]\[ \text{Numerator} = -8a + 16 \][/tex]
[tex]\[ \text{Denominator} = a - 2 \][/tex]
2. Consider the form of the numerator:
Notice that the numerator [tex]\(-8a + 16\)[/tex] can be factored out. First, split 16 as:
[tex]\[ -8a + 16 = -8(a - 2) \][/tex]
3. Rewrite the original division problem using this factorization:
[tex]\[ \frac{-8(a - 2)}{a - 2} \][/tex]
4. Cancel out the common factor in the numerator and denominator:
Since [tex]\(a - 2\)[/tex] appears in both the numerator and the denominator, they cancel out, leaving:
[tex]\[ -8 \][/tex]
So, the result of dividing [tex]\((-8a + 16) \div (a - 2)\)[/tex] is:
[tex]\[ -8 \][/tex]
Thus, the simplified result of the given expression is [tex]\(-8\)[/tex].
1. Identify the numerator and the denominator:
[tex]\[ \text{Numerator} = -8a + 16 \][/tex]
[tex]\[ \text{Denominator} = a - 2 \][/tex]
2. Consider the form of the numerator:
Notice that the numerator [tex]\(-8a + 16\)[/tex] can be factored out. First, split 16 as:
[tex]\[ -8a + 16 = -8(a - 2) \][/tex]
3. Rewrite the original division problem using this factorization:
[tex]\[ \frac{-8(a - 2)}{a - 2} \][/tex]
4. Cancel out the common factor in the numerator and denominator:
Since [tex]\(a - 2\)[/tex] appears in both the numerator and the denominator, they cancel out, leaving:
[tex]\[ -8 \][/tex]
So, the result of dividing [tex]\((-8a + 16) \div (a - 2)\)[/tex] is:
[tex]\[ -8 \][/tex]
Thus, the simplified result of the given expression is [tex]\(-8\)[/tex].
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