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Sean created this table to represent the balance of his loan, [tex]$y$[/tex], over a period of months, [tex]$x$[/tex]. The equation for the line of best fit for Sean's table of data is [tex]$y=-115.9x+8007.30$[/tex].

\begin{tabular}{|r|r|}
\hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline 0 & \[tex]$8,000 \\
\hline 1 & \$[/tex]7,888 \\
\hline 2 & \[tex]$7,775 \\
\hline 3 & \$[/tex]7,661 \\
\hline 4 & \[tex]$7,547 \\
\hline 5 & \$[/tex]7,432 \\
\hline 6 & \[tex]$7,316 \\
\hline 7 & \$[/tex]7,200 \\
\hline 8 & \[tex]$7,083 \\
\hline 9 & \$[/tex]6,966 \\
\hline 10 & \[tex]$6,848 \\
\hline 11 & \$[/tex]6,729 \\
\hline 12 & \[tex]$6,609 \\
\hline
\end{tabular}

According to the line of best fit and using $[/tex]\square[tex]$, Sean can estimate that the balance of his loan will reach \$[/tex]0 in month [tex]$\square$[/tex].

Sagot :

GinnyAnsweridn
According to the line of best fit and using the equation [tex]\(y = -115.9x + 8007.30\)[/tex], Sean can estimate that the balance of his loan will reach [tex]\(\$ 0\)[/tex] in month [tex]\(69.08800690250216\)[/tex].
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