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A movie producer conducted a survey after the screening of his movie to find out how the film would be received by viewers from different age groups. The columns in the two-way table indicate the numbers of viewers who rated the film on a four-point scale: excellent, good, average, and poor.

\begin{tabular}{|c|c|c|c|c|c|}
\hline Viewer's Age Group & Excellent & Good & Average & Poor & Marginal Totals \\
\hline [tex]$16-25$[/tex] & 52 & 42 & 12 & 7 & 113 \\
\hline [tex]$26-35$[/tex] & 33 & 50 & 5 & 9 & 97 \\
\hline [tex]$36-45$[/tex] & 58 & 12 & 28 & 34 & 132 \\
\hline [tex]$46-55$[/tex] & 25 & 17 & 22 & 12 & 76 \\
\hline 56 and Above & 12 & 5 & 3 & 8 & 28 \\
\hline Marginal Totals & 180 & 126 & 70 & 70 & 446 \\
\hline
\end{tabular}

Select the correct answer:
What percentage of the audience from the 16-25 age group gave the movie a poor rating?

A. [tex]$6.19 \%$[/tex]
B. [tex]$10.00 \%$[/tex]
C. [tex]$25.34 \%$[/tex]
D. [tex]$15.70 \%$[/tex]
E. [tex]$16.22 \%$[/tex]


Sagot :

To determine the percentage of viewers aged 16-25 who gave the movie a poor rating, we follow these steps:

1. Identify the total number of viewers in the 16-25 age group: The marginal total for the 16-25 age group, which is the sum of all ratings given, is 113.

2. Identify the number of viewers in the 16-25 age group who gave a poor rating: From the table, 7 viewers in the 16-25 age group rated the movie as poor.

3. Calculate the percentage: To find the percentage, divide the number of 16-25 viewers who rated the movie as poor by the total number of 16-25 viewers, and then multiply by 100 to convert it into a percentage.

[tex]\[ \text{Percentage of poor ratings} = \left( \frac{\text{Number of poor ratings}}{\text{Total number of viewers in 16-25 age group}} \right) \times 100 \][/tex]

Substituting the numbers we have:

[tex]\[ \text{Percentage of poor ratings} = \left( \frac{7}{113} \right) \times 100 \][/tex]

Evaluating this, we get approximately:

[tex]\[ \text{Percentage of poor ratings} \approx 6.19\% \][/tex]

Thus, the correct answer is:
A. [tex]$6.19 \%$[/tex]