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Sagot :
To complete the function table where the output is calculated by adding 4 to each input value, let's proceed step-by-step for each input.
Step 1: Calculate the output for the first input value (-3)
- Input: -3
- Output: -3 + 4
Step 2: Calculate the output for the second input value (1)
- Input: 1
- Output: 1 + 4
Step 3: Calculate the output for the third input value (6)
- Input: 6
- Output: 6 + 4
Now, let's calculate each step:
1. For the input -3:
[tex]\[ -3 + 4 = 1 \][/tex]
2. For the input 1:
[tex]\[ 1 + 4 = 5 \][/tex]
3. For the input 6:
[tex]\[ 6 + 4 = 10 \][/tex]
Thus, the completed function table is:
[tex]\[ \begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ \hline -3 & 1 \\ 1 & 5 \\ 6 & 10 \\ \end{array} \][/tex]
Therefore, the correct completed table looks like this:
[tex]\[ \begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ -3 & 1 \\ 1 & 5 \\ 6 & 10 \\ \end{array} \][/tex]
Comparing this with the given options, the correct completed function table is not option A. The correct function table is as shown above:
[tex]\[ \left[\begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ -3 & 1 \\ 1 & 5 \\ 6 & 10 \end{array}\right] \][/tex]
Step 1: Calculate the output for the first input value (-3)
- Input: -3
- Output: -3 + 4
Step 2: Calculate the output for the second input value (1)
- Input: 1
- Output: 1 + 4
Step 3: Calculate the output for the third input value (6)
- Input: 6
- Output: 6 + 4
Now, let's calculate each step:
1. For the input -3:
[tex]\[ -3 + 4 = 1 \][/tex]
2. For the input 1:
[tex]\[ 1 + 4 = 5 \][/tex]
3. For the input 6:
[tex]\[ 6 + 4 = 10 \][/tex]
Thus, the completed function table is:
[tex]\[ \begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ \hline -3 & 1 \\ 1 & 5 \\ 6 & 10 \\ \end{array} \][/tex]
Therefore, the correct completed table looks like this:
[tex]\[ \begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ -3 & 1 \\ 1 & 5 \\ 6 & 10 \\ \end{array} \][/tex]
Comparing this with the given options, the correct completed function table is not option A. The correct function table is as shown above:
[tex]\[ \left[\begin{array}{c|c} \text { Input }(n) & \text { Output }(n+4) \\ -3 & 1 \\ 1 & 5 \\ 6 & 10 \end{array}\right] \][/tex]
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