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Find the amplitude of [tex]f(x) = 8 \sin \left(6x + \frac{\pi}{4}\right) - 3[/tex].

A. 8
B. 7
C. [tex]\frac{1}{4}[/tex]
D. 5


Sagot :

To find the amplitude of the function [tex]\( f(x) = 8 \sin \left(6 x + \frac{\pi}{4} \right) - 3 \)[/tex], we need to consider the general form of a sinusoidal function, which is given by:

[tex]\[ f(x) = A \sin(Bx + C) + D \][/tex]

In this general form:
- [tex]\( A \)[/tex] is the amplitude
- [tex]\( B \)[/tex] affects the period
- [tex]\( C \)[/tex] is the phase shift
- [tex]\( D \)[/tex] is the vertical shift

For the function [tex]\( f(x) = 8 \sin \left( 6x + \frac{\pi}{4} \right) - 3 \)[/tex], we identify the amplitude [tex]\( A \)[/tex] as the coefficient of the sine function. The coefficient of [tex]\(\sin\)[/tex] here is 8.

Thus, the amplitude of the function [tex]\( f(x) = 8 \sin \left(6 x + \frac{\pi}{4} \right) - 3 \)[/tex] is:

[tex]\[ \boxed{8} \][/tex]