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A charge of [tex]$8.5 \times 10^{-6} C$[/tex] is in an electric field that has a strength of [tex]$3.2 \times 10^5 \, N/C$[/tex]. What is the electric force acting on the charge?

A. 0.27 N
B. 2.7 N
C. 27 N
D. 270 N

Sagot :

GinnyAnsweridn
To find the electric force acting on a charge in an electric field, we use the formula:

[tex]\[ F = qE \][/tex]

where:
- [tex]\( F \)[/tex] is the electric force,
- [tex]\( q \)[/tex] is the charge,
- [tex]\( E \)[/tex] is the electric field strength.

Given:
- The charge [tex]\( q = 8.5 \times 10^{-6} \)[/tex] Coulombs,
- The electric field strength [tex]\( E = 3.2 \times 10^5 \)[/tex] Newtons per Coulomb.

Now, we substitute the given values into the formula:

[tex]\[ F = (8.5 \times 10^{-6} \, \text{C}) \times (3.2 \times 10^5 \, \text{N/C}) \][/tex]

Multiplying these values, we get:

[tex]\[ F = 2.72 \, \text{N} \][/tex]

Thus, the electric force acting on the charge is:

[tex]\[ 2.72 \, \text{N} \][/tex]

So, the correct answer is [tex]\( 2.7 \, \text{N} \)[/tex] as it is the closest in the given options.
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