Find expert answers and community insights on IDNLearn.com. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.

Which expressions are equivalent to [tex]\frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5}[/tex]?

Choose 2 answers:

A. [tex](5^{-2})^2[/tex]
B. [tex](5^{-4})^0[/tex]
C. [tex]\frac{5^1}{5^4}[/tex]
D. [tex]5^2 \cdot 5^{-6}[/tex]


Sagot :

To determine which expressions are equivalent to [tex]\(\frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5}\)[/tex], we need to simplify each given option and then compare them to the original expression.

1. Let's simplify the original expression:
[tex]\[ \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} \][/tex]
This can be rewritten as:
[tex]\[ \left(\frac{1}{5}\right)^4 = 5^{-4} \][/tex]

2. Now let’s evaluate each option one by one to find out which are equivalent to [tex]\(5^{-4}\)[/tex]:

Option A: [tex]\(\left(5^{-2}\right)^2\)[/tex]
[tex]\[ (5^{-2})^2 = 5^{-2 \cdot 2} = 5^{-4} \][/tex]
Thus, [tex]\(\left(5^{-2}\right)^2 = 5^{-4}\)[/tex], which is correct.

Option B: [tex]\(\left(5^{-4}\right)^0\)[/tex]
[tex]\[ (5^{-4})^0 = 5^{0} = 1 \][/tex]
This is not equivalent to [tex]\(5^{-4}\)[/tex], so this option is incorrect.

Option C: [tex]\(\frac{5^1}{5^4}\)[/tex]
[tex]\[ \frac{5^1}{5^4} = 5^{1-4} = 5^{-3} \][/tex]
This is not equivalent to [tex]\(5^{-4}\)[/tex], so this option is incorrect.

Option D: [tex]\(5^2 \cdot 5^{-6}\)[/tex]
[tex]\[ 5^2 \cdot 5^{-6} = 5^{2 + (-6)} = 5^{-4} \][/tex]
Thus, [tex]\(5^2 \cdot 5^{-6} = 5^{-4}\)[/tex], which is correct.

Hence, the expressions equivalent to [tex]\(\frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5}\)[/tex] are:

- [tex]\(\left(5^{-2}\right)^2\)[/tex]
- [tex]\(5^2 \cdot 5^{-6}\)[/tex]

So, the two correct options are:
- (A) [tex]\(\left(5^{-2}\right)^2\)[/tex]
- (D) [tex]\(5^2 \cdot 5^{-6}\)[/tex]
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.