IDNLearn.com provides a user-friendly platform for finding and sharing knowledge. Ask your questions and get detailed, reliable answers from our community of knowledgeable experts.

Polygon [tex]$ABCD$[/tex] is dilated by a scale factor of 2 with the center of dilation at the origin to create polygon [tex]$A'B'C'D'$[/tex]. If the endpoints of [tex]$\overline{AB}$[/tex] are located at [tex]$(0, -7)$[/tex] and [tex]$(8, 8)$[/tex], what is the length of [tex]$\overline{A'B'}$[/tex]?

Use the distance formula to help you decide:
[tex]\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\][/tex]


Sagot :

To solve this problem, we need to determine the length of segment [tex]\( \overline{A'B'} \)[/tex] after dilation when the original segment [tex]\( \overline{AB} \)[/tex] is dilated by a scale factor of 2.

First, we start by identifying the coordinates of the endpoints of [tex]\( \overline{AB} \)[/tex]:
- Coordinates of point [tex]\( A \)[/tex]: [tex]\( (0, -7) \)[/tex]
- Coordinates of point [tex]\( B \)[/tex]: [tex]\( (8, 8) \)[/tex]

Next, we need to calculate the length of segment [tex]\( \overline{AB} \)[/tex] using the distance formula:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

Plugging in the coordinates of points [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:
[tex]\[ d_{AB} = \sqrt{(8 - 0)^2 + (8 - (-7))^2} \][/tex]
[tex]\[ d_{AB} = \sqrt{8^2 + (8 + 7)^2} \][/tex]
[tex]\[ d_{AB} = \sqrt{64 + 15^2} \][/tex]
[tex]\[ d_{AB} = \sqrt{64 + 225} \][/tex]
[tex]\[ d_{AB} = \sqrt{289} \][/tex]
[tex]\[ d_{AB} = 17 \][/tex]

Now, we need to find the length of segment [tex]\( \overline{A'B'} \)[/tex] after the dilation by a scale factor of 2. In a dilation with the center at the origin, each length is scaled by the scale factor. Therefore, the length of [tex]\( \overline{A'B'} \)[/tex] is:
[tex]\[ d_{A'B'} = 2 \times d_{AB} \][/tex]
[tex]\[ d_{A'B'} = 2 \times 17 \][/tex]
[tex]\[ d_{A'B'} = 34 \][/tex]

Therefore, the length of [tex]\( \overline{A'B'} \)[/tex] is [tex]\( 34 \)[/tex].
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.