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If the velocity of a 0.02 kg bullet is [tex]500 \, \text{m/s}[/tex], find the magnitude of the momentum of the bullet. If the bullet is fired towards the north, what is the direction of its momentum?

Sagot :

To determine the magnitude and direction of the momentum of a bullet, we'll use the following physical concepts and steps:

### Step-by-Step Solution

1. Identify Given Values:
- Mass ([tex]\(m\)[/tex]) of the bullet: 0.02 kg
- Velocity ([tex]\(v\)[/tex]) of the bullet: 500 m/s

2. Understand the Concept of Momentum:
- Momentum ([tex]\(p\)[/tex]) is defined as the product of mass and velocity.
- The formula for momentum is: [tex]\(p = m \times v\)[/tex]

3. Calculate the Magnitude of the Momentum:
Substitute the given values into the formula:

[tex]\[ p = 0.02 \, \text{kg} \times 500 \, \text{m/s} \][/tex]

Compute the result:

[tex]\[ p = 10.0 \, \text{kg} \cdot \text{m/s} \][/tex]

4. Determine the Direction of the Momentum:
- Momentum is a vector quantity, meaning it has both magnitude and direction.
- The direction of the momentum is the same as the direction of the velocity.
- Since the bullet is fired towards the north, the direction of its momentum is also towards the north.

### Final Answer:
- The magnitude of the momentum of the bullet is [tex]\(10.0 \, \text{kg} \cdot \text{m/s}\)[/tex].
- The direction of the bullet's momentum is towards the north.

Thus, the magnitude of the momentum of the bullet is [tex]\(10.0 \, \text{kg} \cdot \text{m/s}\)[/tex] and its direction is north.