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Answer:
Step-by-step explanation:
To find the 36th term in the sequence 20, 16, 12, 8, we need to identify the pattern and determine if it's an arithmetic or geometric sequence .Given the terms:
given 1st term 20...... 2nd term 16..... 3rd term 12,,,,,, 4th term 8 The common difference (
d) can be found by subtracting the first term from the second term:
=
16
−
20
=
−
4
d=16−20=−4 he general formula for the
nth term of an arithmetic sequence is:
=
1
+
(
−
1
)
a
n
=a
1
+(n−1)d o find the 36th term (
36
a
36
):
36
=
20
+
(
36
−
1
)
(
−
4
)
a
36
=20+(36−1)(−4)
36
=
20
+
35
(
−
4
)
a
36
=20+35(−4)
36
=
20
−
140
a
36
=20−140
36
=
−
120
a
36
=−120
Therefore, the 36th term is
−
120
−120.