To determine which description fits Myra's distance as time increases, let's analyze the given data step-by-step.
We have the following data:
| Time (minutes) | Distance (miles) |
|----------------|------------------|
| 0 | 0.0 |
| 2 | 0.4 |
| 4 | 0.8 |
| 6 | 1.2 |
| 8 | 1.6 |
First, let's calculate the rate of change of the distance for each time interval.
### Interval Calculations:
1. From 0 to 2 minutes:
[tex]\[
\text{Rate of change} = \frac{0.4 - 0.0}{2 - 0} = \frac{0.4}{2} = 0.2 \text{ miles per minute}
\][/tex]
2. From 2 to 4 minutes:
[tex]\[
\text{Rate of change} = \frac{0.8 - 0.4}{4 - 2} = \frac{0.4}{2} = 0.2 \text{ miles per minute}
\][/tex]
3. From 4 to 6 minutes:
[tex]\[
\text{Rate of change} = \frac{1.2 - 0.8}{6 - 4} = \frac{0.4}{2} = 0.2 \text{ miles per minute}
\][/tex]
4. From 6 to 8 minutes:
[tex]\[
\text{Rate of change} = \frac{1.6 - 1.2}{8 - 6} = \frac{0.4}{2} = 0.2 \text{ miles per minute}
\][/tex]
Now, we have the rates of change for each interval:
[tex]\[
[0.2, 0.2, 0.2, 0.2]
\][/tex]
### Determination:
Next, we need to describe the trend in the rates of change:
- All calculated rates of change are [tex]\(0.2\)[/tex], which means the rate of change is positive and consistent across all intervals.
Therefore, Myra's distance is steadily increasing as time increases. Given these rates of change:
[tex]\[
0.2 \text{ miles per minute (from 0 to 2 minutes)}
0.2 \text{ miles per minute (from 2 to 4 minutes)}
0.2 \text{ miles per minute (from 4 to 6 minutes)}
0.2 \text{ miles per minute (from 6 to 8 minutes)}
\][/tex]
The description that fits Myra's distance over time is increasing since her distance keeps increasing at a constant rate as time goes on.
So, the final answer to the question is:
increasing
