From everyday questions to specialized queries, IDNLearn.com has the answers. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.
Sagot :
To solve the given expression [tex]\((m-7)(m+2)\)[/tex], we will use the distributive property, often referred to as the FOIL method (First, Outer, Inner, Last). Here is the detailed step-by-step solution:
1. First Terms (F):
Multiply the first terms in each binomial:
[tex]\[ m \cdot m = m^2 \][/tex]
2. Outer Terms (O):
Multiply the outer terms in the binomials:
[tex]\[ m \cdot 2 = 2m \][/tex]
3. Inner Terms (I):
Multiply the inner terms in the binomials:
[tex]\[ -7 \cdot m = -7m \][/tex]
4. Last Terms (L):
Multiply the last terms in each binomial:
[tex]\[ -7 \cdot 2 = -14 \][/tex]
5. Combine All Terms:
Now, we need to sum all these products together:
[tex]\[ m^2 + 2m - 7m - 14 \][/tex]
6. Simplify the Expression:
Combine the like terms ([tex]\(2m\)[/tex] and [tex]\(-7m\)[/tex]):
[tex]\[ m^2 + (2m - 7m) - 14 = m^2 - 5m - 14 \][/tex]
So, the simplified form of the expression [tex]\((m-7)(m+2)\)[/tex] is:
[tex]\[ m^2 - 5m - 14 \][/tex]
1. First Terms (F):
Multiply the first terms in each binomial:
[tex]\[ m \cdot m = m^2 \][/tex]
2. Outer Terms (O):
Multiply the outer terms in the binomials:
[tex]\[ m \cdot 2 = 2m \][/tex]
3. Inner Terms (I):
Multiply the inner terms in the binomials:
[tex]\[ -7 \cdot m = -7m \][/tex]
4. Last Terms (L):
Multiply the last terms in each binomial:
[tex]\[ -7 \cdot 2 = -14 \][/tex]
5. Combine All Terms:
Now, we need to sum all these products together:
[tex]\[ m^2 + 2m - 7m - 14 \][/tex]
6. Simplify the Expression:
Combine the like terms ([tex]\(2m\)[/tex] and [tex]\(-7m\)[/tex]):
[tex]\[ m^2 + (2m - 7m) - 14 = m^2 - 5m - 14 \][/tex]
So, the simplified form of the expression [tex]\((m-7)(m+2)\)[/tex] is:
[tex]\[ m^2 - 5m - 14 \][/tex]
We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.