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Sagot :
Sheena wants to measure the volume of a ball (sphere) with a diameter of 24 cm.
To find the volume of a sphere, we use the formula:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]
Here, [tex]\( r \)[/tex] is the radius of the sphere. The radius is half of the diameter. Given that the diameter is 24 cm, the radius [tex]\( r \)[/tex] can be calculated as:
[tex]\[ r = \frac{24}{2} = 12 \text{ cm} \][/tex]
Now, substituting [tex]\( r = 12 \text{ cm} \)[/tex] into the volume formula, we get:
[tex]\[ V = \frac{4}{3} \pi (12)^3 \][/tex]
So, the correct setup for the equation is:
[tex]\[ V = \frac{4}{3} \pi 12^3 \][/tex]
Therefore, the correct choice is:
[tex]\[ V = \frac{4}{3} \pi 12^3 \][/tex]
To find the volume of a sphere, we use the formula:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]
Here, [tex]\( r \)[/tex] is the radius of the sphere. The radius is half of the diameter. Given that the diameter is 24 cm, the radius [tex]\( r \)[/tex] can be calculated as:
[tex]\[ r = \frac{24}{2} = 12 \text{ cm} \][/tex]
Now, substituting [tex]\( r = 12 \text{ cm} \)[/tex] into the volume formula, we get:
[tex]\[ V = \frac{4}{3} \pi (12)^3 \][/tex]
So, the correct setup for the equation is:
[tex]\[ V = \frac{4}{3} \pi 12^3 \][/tex]
Therefore, the correct choice is:
[tex]\[ V = \frac{4}{3} \pi 12^3 \][/tex]
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