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Sagot :
Let's walk through the solution step by step.
Ashley has 7 quarters. Each quarter is worth [tex]$0.25. To find out the total value of these quarters, we multiply the number of quarters by the value of each quarter: \[ \text{Total value of quarters} = 7 \times 0.25 = 1.75 \, \text{dollars}\] So, the total value of the quarters Ashley has is $[/tex]1.75.
Ashley needs at least [tex]$3.00 to pay for her lunch. This means that the combined value of the quarters and dimes in her purse has to be equal to or more than $[/tex]3.00.
Let [tex]\( d \)[/tex] be the number of dimes she has. Each dime is worth [tex]$0.10. Therefore, the total value of the dimes is: \[ 0.10d \] Combining the value of the quarters and the value of the dimes, the total amount of money Ashley has is: \[ 1.75 + 0.10d \] We need this total to be at least $[/tex]3.00 to satisfy her need. So the inequality we can write is:
[tex]\[ 1.75 + 0.10d \geq 3.00 \][/tex]
So, the correct inequality to determine the number of dimes [tex]\( d \)[/tex] Ashley needs is:
[tex]\[ (2) \, 1.75 + 0.10d \geq 3.00 \][/tex]
Ashley has 7 quarters. Each quarter is worth [tex]$0.25. To find out the total value of these quarters, we multiply the number of quarters by the value of each quarter: \[ \text{Total value of quarters} = 7 \times 0.25 = 1.75 \, \text{dollars}\] So, the total value of the quarters Ashley has is $[/tex]1.75.
Ashley needs at least [tex]$3.00 to pay for her lunch. This means that the combined value of the quarters and dimes in her purse has to be equal to or more than $[/tex]3.00.
Let [tex]\( d \)[/tex] be the number of dimes she has. Each dime is worth [tex]$0.10. Therefore, the total value of the dimes is: \[ 0.10d \] Combining the value of the quarters and the value of the dimes, the total amount of money Ashley has is: \[ 1.75 + 0.10d \] We need this total to be at least $[/tex]3.00 to satisfy her need. So the inequality we can write is:
[tex]\[ 1.75 + 0.10d \geq 3.00 \][/tex]
So, the correct inequality to determine the number of dimes [tex]\( d \)[/tex] Ashley needs is:
[tex]\[ (2) \, 1.75 + 0.10d \geq 3.00 \][/tex]
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