Find the best answers to your questions with the help of IDNLearn.com's knowledgeable users. Get prompt and accurate answers to your questions from our experts who are always ready to help.
Sagot :
To determine which of the given solutions would have a pH greater than 7.00, we need to consider the nature of each compound (whether it forms acidic, basic, or neutral solutions when dissolved in water).
1. [tex]$NH_4Br$[/tex]:
- [tex]$NH_4^+$[/tex] (ammonium ion) is a weak acid.
- [tex]$Br^-$[/tex] (bromide ion) is a neutral ion because it comes from the strong acid HBr.
- Hence, [tex]$NH_4Br$[/tex] in water will produce a slightly acidic solution, and the pH will be less than 7.
2. [tex]$C_6H_5NH_3Br$[/tex] (aniline hydrobromide):
- [tex]$C_6H_5NH_3^+$[/tex] (anilinium ion) is a weak acid.
- [tex]$Br^-$[/tex] is neutral.
- This will also result in a slightly acidic solution, and the pH will be less than 7.
3. [tex]$Ca(NO_3)_2$[/tex] (calcium nitrate):
- Both [tex]$Ca^{2+}$[/tex] and [tex]$NO_3^-$[/tex] are neutral ions (since [tex]$NO_3^-$[/tex] comes from a strong acid [tex]$HNO_3$[/tex] and [tex]$Ca^{2+}$[/tex] does not affect pH).
- Therefore, [tex]$Ca(NO_3)_2$[/tex] results in a neutral solution with a pH around 7.
4. [tex]$C_6H_5COONa$[/tex] (sodium benzoate):
- [tex]$C_6H_5COO^-$[/tex] (benzoate ion) is the conjugate base of benzoic acid, which is a weak acid.
- [tex]$Na^+$[/tex] is a neutral ion.
- The benzoate ion will hydrolyze in water to produce [tex]$OH^-$[/tex] ions, making the solution basic.
- Hence, [tex]$C_6H_5COONa$[/tex] will have a pH greater than 7.
Based on this analysis, the compound that would be expected to have a pH greater than 7.00 is:
D. [tex]$C_6H_5COONa$[/tex].
1. [tex]$NH_4Br$[/tex]:
- [tex]$NH_4^+$[/tex] (ammonium ion) is a weak acid.
- [tex]$Br^-$[/tex] (bromide ion) is a neutral ion because it comes from the strong acid HBr.
- Hence, [tex]$NH_4Br$[/tex] in water will produce a slightly acidic solution, and the pH will be less than 7.
2. [tex]$C_6H_5NH_3Br$[/tex] (aniline hydrobromide):
- [tex]$C_6H_5NH_3^+$[/tex] (anilinium ion) is a weak acid.
- [tex]$Br^-$[/tex] is neutral.
- This will also result in a slightly acidic solution, and the pH will be less than 7.
3. [tex]$Ca(NO_3)_2$[/tex] (calcium nitrate):
- Both [tex]$Ca^{2+}$[/tex] and [tex]$NO_3^-$[/tex] are neutral ions (since [tex]$NO_3^-$[/tex] comes from a strong acid [tex]$HNO_3$[/tex] and [tex]$Ca^{2+}$[/tex] does not affect pH).
- Therefore, [tex]$Ca(NO_3)_2$[/tex] results in a neutral solution with a pH around 7.
4. [tex]$C_6H_5COONa$[/tex] (sodium benzoate):
- [tex]$C_6H_5COO^-$[/tex] (benzoate ion) is the conjugate base of benzoic acid, which is a weak acid.
- [tex]$Na^+$[/tex] is a neutral ion.
- The benzoate ion will hydrolyze in water to produce [tex]$OH^-$[/tex] ions, making the solution basic.
- Hence, [tex]$C_6H_5COONa$[/tex] will have a pH greater than 7.
Based on this analysis, the compound that would be expected to have a pH greater than 7.00 is:
D. [tex]$C_6H_5COONa$[/tex].
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.