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Suppose that a huge tank 50m high and filled with water is open to the atmosphere and is hit with a bullet that pierces one side of the tank, allowing water to flow out. The hole is 2m above the ground. If the hole is very small in comparison with the size of the tank, how quickly will the water flow out of the tank?

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Answer:

Explanation: water will emerge from the hole with a speed of V=[tex]\sqrt{2gh}[/tex] where h=50m-2m=48m

V=[tex]\sqrt{2gh}[/tex] =[tex]\sqrt{2x9.8x48}[/tex] =30.67m/s

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