Answered

IDNLearn.com: Your trusted source for accurate and reliable answers. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

What is the value of this expression when [tex]$x = -6$[/tex] and [tex]$y = -\frac{1}{2}$[/tex]?

[tex]4\left(x^2 + 3\right) - 2y[/tex]

A. -131
B. -35
C. [tex][tex]$57 \frac{1}{2}$[/tex][/tex]
D. 157

Sagot :

GinnyAnsweridn
Let's solve the expression step-by-step: [tex]\( 4\left(x^2 + 3\right) - 2y \)[/tex] when [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex].

1. Calculate [tex]\( x^2 \)[/tex]:
- Given [tex]\( x = -6 \)[/tex]
- [tex]\( x^2 = (-6)^2 = 36 \)[/tex]

2. Substitute [tex]\( x^2 \)[/tex] into the expression [tex]\( x^2 + 3 \)[/tex]:
- [tex]\( x^2 + 3 = 36 + 3 = 39 \)[/tex]

3. Multiply the result by 4:
- [tex]\( 4(x^2 + 3) = 4 \times 39 = 156 \)[/tex]

4. Calculate [tex]\( -2y \)[/tex]:
- Given [tex]\( y = -\frac{1}{2} \)[/tex]
- [tex]\( -2y = -2 \times -\frac{1}{2} = 1 \)[/tex]

5. Combine the results:
- The expression becomes [tex]\( 156 + 1 = 157 \)[/tex]

So, the value of the expression [tex]\( 4\left(x^2 + 3\right) - 2y \)[/tex] when [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex] is [tex]\( 157 \)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{157} \][/tex]

Answer:

D. 157

Step-by-step explanation:

Answer this question using the mathematical process of substitution!

First, rewrite your original equation by replacing x with -6 and y with [tex]-\frac{1}{2}[/tex]:

[tex]4 [(-6)^{2} +3] -2(-\frac{1}{2} )[/tex]

Next, solve following the rules of PEMDAS:

  1. Solve the equation is in the parenthesis: [tex][(-6)^{2} +3][/tex]= 36 +3= 39. The equation is now [tex]4(39) - 2(-\frac{1}{2} )[/tex]
  2. Next, multiply values together: 4×39= 156  ,  -2 ×[tex]-\frac{1}{2}[/tex]= 1. The equation is now 156 + 1.
  3. Add the two values.

Your answer is 157

Learn more about substitution here: https://brainly.com/question/30239658

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Thank you for choosing IDNLearn.com for your queries. We’re here to provide accurate answers, so visit us again soon.