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Solve for [tex]\( x \)[/tex] and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not.

[tex]\[ \sqrt{11x + 5} = 7 \][/tex]


Sagot :

To solve the equation [tex]\(\sqrt{11x + 5} = 7\)[/tex], let's follow a systematic approach:

### Step 1: Isolate the square root

The equation we start with is:
[tex]\[ \sqrt{11x + 5} = 7 \][/tex]

### Step 2: Eliminate the square root

To eliminate the square root, we square both sides of the equation:
[tex]\[ (\sqrt{11x + 5})^2 = 7^2 \][/tex]
This simplifies to:
[tex]\[ 11x + 5 = 49 \][/tex]

### Step 3: Solve for [tex]\( x \)[/tex]

Next, isolate [tex]\(x\)[/tex] by performing algebraic operations:
[tex]\[ 11x + 5 = 49 \][/tex]
Subtract 5 from both sides of the equation:
[tex]\[ 11x = 44 \][/tex]
Divide both sides by 11:
[tex]\[ x = 4 \][/tex]

### Step 4: Verify the solution

To ensure the solution [tex]\( x = 4 \)[/tex] is not extraneous, we substitute [tex]\( x = 4 \)[/tex] back into the original equation and check if it holds true:
[tex]\[ \sqrt{11(4) + 5} = 7 \][/tex]
Simplify inside the square root:
[tex]\[ \sqrt{44 + 5} = 7 \][/tex]
[tex]\[ \sqrt{49} = 7 \][/tex]

Since [tex]\(\sqrt{49} = 7\)[/tex], the original equation is satisfied, confirming that our solution is correct.

### Conclusion

The solution to the equation [tex]\(\sqrt{11x + 5} = 7\)[/tex] is:
[tex]\[ x = 4 \][/tex]

This solution is not extraneous, as substituting it back into the original equation verifies that it satisfies the equation.