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Sagot :
To determine which event is more likely, we need to compare the probabilities of Paulina getting injured while playing volleyball and soccer.
1. Probability of getting injured playing volleyball:
The given probability is 0.1.
2. Probability of getting injured playing soccer:
The given probability is [tex]\(\frac{1}{10}\)[/tex].
First, observe that the probability of getting injured playing soccer [tex]\(\frac{1}{10}\)[/tex] can be converted to decimal form:
[tex]\[ \frac{1}{10} = 0.1 \][/tex]
Now, let's compare the two probabilities:
- Probability of getting injured in volleyball = 0.1
- Probability of getting injured in soccer = 0.1
Since both probabilities are equal (0.1 = 0.1), neither event is more likely than the other.
Therefore, the answer is:
(C) Neither. Both events are equally likely.
1. Probability of getting injured playing volleyball:
The given probability is 0.1.
2. Probability of getting injured playing soccer:
The given probability is [tex]\(\frac{1}{10}\)[/tex].
First, observe that the probability of getting injured playing soccer [tex]\(\frac{1}{10}\)[/tex] can be converted to decimal form:
[tex]\[ \frac{1}{10} = 0.1 \][/tex]
Now, let's compare the two probabilities:
- Probability of getting injured in volleyball = 0.1
- Probability of getting injured in soccer = 0.1
Since both probabilities are equal (0.1 = 0.1), neither event is more likely than the other.
Therefore, the answer is:
(C) Neither. Both events are equally likely.
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