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Which equation represents a circle with a center at [tex]\((-5, 5)\)[/tex] and a radius of 3 units?

A. [tex]\((x - 5)^2 + (y + 5)^2 = 9\)[/tex]

B. [tex]\((x + 5)^2 + (y - 5)^2 = 6\)[/tex]

C. [tex]\((x + 5)^2 + (y - 5)^2 = 9\)[/tex]

D. [tex]\((x - 5)^2 + (y + 5)^2 = 3\)[/tex]

E. [tex]\((x + 5)^2 + (y - 5)^2 = 3\)[/tex]


Sagot :

To find the equation of a circle given its center and radius, we use the standard form of the equation of a circle:

[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]

where [tex]\((h, k)\)[/tex] is the center of the circle, and [tex]\(r\)[/tex] is the radius.

Let's analyze the given problem:
- Center of the circle [tex]\((h, k) = (-5, 5)\)[/tex]
- Radius [tex]\(r = 3\)[/tex]

Substituting the center and radius into the standard form equation, we get:

[tex]\[ (x - (-5))^2 + (y - 5)^2 = 3^2 \][/tex]

Simplify this equation:
[tex]\[ (x + 5)^2 + (y - 5)^2 = 9 \][/tex]

Thus, the equation of the circle is:
[tex]\[ (x + 5)^2 + (y - 5)^2 = 9 \][/tex]

Now, we compare this result with the provided options:
- A. [tex]\((x-5)^2+(y+5)^2=9\)[/tex] does not match our derived equation because the signs inside the parentheses are incorrect.
- B. [tex]\((x+5)^2+(y-5)^2=6\)[/tex] does not match our derived equation because the right-hand side is 6 instead of 9.
- C. [tex]\((x+5)^2+(y-5)^2=9\)[/tex] exactly matches our derived equation.
- D. [tex]\((x-5)^2+(y+5)^2=3\)[/tex] does not match our derived equation because both the left-hand side and right-hand side are incorrect.
- E. [tex]\((x+5)^2+(y-5)^2=3\)[/tex] does not match our derived equation because the right-hand side is 3 instead of 9.

Therefore, the correct answer is:

[tex]\[ \boxed{C} \][/tex]