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Sagot :
To find the equation of the line given the slope [tex]\( m \)[/tex] and the y-intercept [tex]\( b \)[/tex], we use the slope-intercept form of a linear equation. The general form of the slope-intercept equation is:
[tex]\[ y = mx + b \][/tex]
Here, [tex]\( m \)[/tex] represents the slope of the line, and [tex]\( b \)[/tex] represents the y-intercept, which is the point where the line crosses the y-axis.
Given the values:
- Slope ([tex]\( m \)[/tex]) = -6
- Y-intercept ([tex]\( b \)[/tex]) = 4
We simply substitute these values into the slope-intercept form equation:
[tex]\[ y = -6x + 4 \][/tex]
Therefore, the equation of the line with a slope of -6 and a y-intercept of 4 is:
[tex]\[ y = -6x + 4 \][/tex]
[tex]\[ y = mx + b \][/tex]
Here, [tex]\( m \)[/tex] represents the slope of the line, and [tex]\( b \)[/tex] represents the y-intercept, which is the point where the line crosses the y-axis.
Given the values:
- Slope ([tex]\( m \)[/tex]) = -6
- Y-intercept ([tex]\( b \)[/tex]) = 4
We simply substitute these values into the slope-intercept form equation:
[tex]\[ y = -6x + 4 \][/tex]
Therefore, the equation of the line with a slope of -6 and a y-intercept of 4 is:
[tex]\[ y = -6x + 4 \][/tex]
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