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Find the equation of the line with the given slope and y-intercept.

Given:
[tex]\[ m = -6 \][/tex]
[tex]\[ b = 4 \][/tex]


Sagot :

To find the equation of the line given the slope [tex]\( m \)[/tex] and the y-intercept [tex]\( b \)[/tex], we use the slope-intercept form of a linear equation. The general form of the slope-intercept equation is:

[tex]\[ y = mx + b \][/tex]

Here, [tex]\( m \)[/tex] represents the slope of the line, and [tex]\( b \)[/tex] represents the y-intercept, which is the point where the line crosses the y-axis.

Given the values:
- Slope ([tex]\( m \)[/tex]) = -6
- Y-intercept ([tex]\( b \)[/tex]) = 4

We simply substitute these values into the slope-intercept form equation:

[tex]\[ y = -6x + 4 \][/tex]

Therefore, the equation of the line with a slope of -6 and a y-intercept of 4 is:

[tex]\[ y = -6x + 4 \][/tex]
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