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If the scale factor between two circles is [tex]\frac{2x}{5y}[/tex], what is the ratio of their areas?

A. [tex]\frac{2x}{5y}[/tex]

B. [tex]\frac{2x^2}{5y^2}[/tex]

C. [tex]\frac{4x^2 \pi}{25y^2}[/tex]

D. [tex]\frac{4x^2}{25y^2}[/tex]


Sagot :

To determine the ratio of the areas of two circles given a specific scale factor, we need to understand how scaling affects the area of a circle. Specifically, if the linear dimensions (like radius) of a circle are scaled by a factor, the area of the circle scales by the square of that factor.

Let's break it down step-by-step:

1. Given scale factor: The scale factor between the two circles is [tex]\(\frac{2x}{5y}\)[/tex].

2. Understanding the effect on areas: The area of a circle is proportional to the square of its radius. This means if the radius of the second circle is [tex]\(\frac{2x}{5y}\)[/tex] times the radius of the first circle, then the area of the second circle is [tex]\(\left(\frac{2x}{5y}\right)^2\)[/tex] times the area of the first circle.

3. Calculate the ratio of the areas:
[tex]\[ \text{Ratio of the areas} = \left(\frac{2x}{5y}\right)^2 = \frac{(2x)^2}{(5y)^2} = \frac{4x^2}{25y^2}. \][/tex]

Thus, the ratio of their areas is [tex]\(\frac{4x^2}{25y^2}\)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{\frac{4 x^2}{25 y^2}} \][/tex]