IDNLearn.com provides a seamless experience for finding accurate answers. Ask your questions and receive prompt, detailed answers from our experienced and knowledgeable community members.
Sagot :
To determine which function defines [tex]\((f+g)(x)\)[/tex], we first need to understand the individual functions [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
Given:
[tex]\[ f(x) = \ln(2x) - 15 \][/tex]
[tex]\[ g(x) = 3 \sin(x) - 7 \][/tex]
To find [tex]\((f+g)(x)\)[/tex], we simply add [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ (f+g)(x) = f(x) + g(x) \][/tex]
Substitute the expressions for [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ (f+g)(x) = (\ln(2x) - 15) + (3 \sin(x) - 7) \][/tex]
Combine the terms:
[tex]\[ (f+g)(x) = \ln(2x) - 15 + 3 \sin(x) - 7 \][/tex]
Simplify the expression by combining the constants:
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 15 - 7 \][/tex]
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 22 \][/tex]
So, the function that defines [tex]\((f+g)(x)\)[/tex] is:
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 22 \][/tex]
The correct answer is:
B. [tex]\((f+g)(x) = \ln(2x) + 3 \sin(x) - 22\)[/tex]
Given:
[tex]\[ f(x) = \ln(2x) - 15 \][/tex]
[tex]\[ g(x) = 3 \sin(x) - 7 \][/tex]
To find [tex]\((f+g)(x)\)[/tex], we simply add [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ (f+g)(x) = f(x) + g(x) \][/tex]
Substitute the expressions for [tex]\(f(x)\)[/tex] and [tex]\(g(x)\)[/tex]:
[tex]\[ (f+g)(x) = (\ln(2x) - 15) + (3 \sin(x) - 7) \][/tex]
Combine the terms:
[tex]\[ (f+g)(x) = \ln(2x) - 15 + 3 \sin(x) - 7 \][/tex]
Simplify the expression by combining the constants:
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 15 - 7 \][/tex]
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 22 \][/tex]
So, the function that defines [tex]\((f+g)(x)\)[/tex] is:
[tex]\[ (f+g)(x) = \ln(2x) + 3 \sin(x) - 22 \][/tex]
The correct answer is:
B. [tex]\((f+g)(x) = \ln(2x) + 3 \sin(x) - 22\)[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.