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Ago and Mike shared a box of popcorn. If they ate all the popcorn in the box and Mike ate three times as much popcorn as Ago, what percent of the popcorn did Ago eat?

Sagot :

GinnyAnsweridn
Sure, let's break down the problem step-by-step:

1. Define Variables:
- Let "H" represent the amount of popcorn that Hat ate.
- Let "M" represent the amount of popcorn that Mike ate.

2. Given Relationship:
- Mike ate three times as much popcorn as Hat.
- Therefore, [tex]\( M = 3H \)[/tex].

3. Total Popcorn Eaten:
- The total amount of popcorn eaten by both Hat and Mike combined is [tex]\( H + M \)[/tex].

4. Substitute the Relationship:
- Substituting [tex]\( M \)[/tex] in the total gives:
[tex]\[ \text{Total Popcorn} = H + 3H = 4H \][/tex]

5. Calculate the Percentage:
- The percentage of the total amount of popcorn eaten by Hat can be calculated by:
[tex]\[ \text{Percentage} = \left(\frac{H}{4H}\right) \times 100 \][/tex]

6. Simplification:
- Simplifying inside the parentheses:
[tex]\[ \text{Percentage} = \left(\frac{1}{4}\right) \times 100 = 25\% \][/tex]

So, Hat ate 25% of the total popcorn.
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