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To minimize the objective function [tex]\( z = 2x + y \)[/tex] subject to the given constraints:
1. [tex]\( 2y + 3x \geq 16 \)[/tex]
2. [tex]\( 5y + 4x \geq 32 \)[/tex]
3. [tex]\( y + x \geq 7 \)[/tex]
4. [tex]\( x \geq 0 \)[/tex]
5. [tex]\( y \geq 0 \)[/tex]
we follow a systematic approach.
### Step 1: Define the Constraints
First, let's rewrite the inequalities in standard form to understand the feasible region:
- [tex]\( 2y + 3x \geq 16 \)[/tex]
- [tex]\( 5y + 4x \geq 32 \)[/tex]
- [tex]\( y + x \geq 7 \)[/tex]
Additionally, we have non-negativity constraints: [tex]\( x \geq 0 \)[/tex] and [tex]\( y \geq 0 \)[/tex].
### Step 2: Find the Feasible Region
The feasible region is defined by the intersection of the half-planes formed by these inequalities.
### Step 3: Determine Corner Points of the Feasible Region
To minimize the objective function linearly, we need to find the points where the constraint lines intersect. Let's identify some of these points:
1. Intersection of [tex]\( 2y + 3x = 16 \)[/tex] and [tex]\( 5y + 4x = 32 \)[/tex]
2. Intersection of [tex]\( 2y + 3x = 16 \)[/tex] and [tex]\( y + x = 7 \)[/tex]
3. Intersection of [tex]\( 5y + 4x = 32 \)[/tex] and [tex]\( y + x = 7 \)[/tex]
4. Check intersections with the axes, since non-negativity bounds might also be relevant.
### Step 4: Compute the Objective Function
Having identified potential intersection points, we calculate the value of [tex]\( z = 2x + y \)[/tex] for each point and compare them to find the minimum value:
1. Evaluate [tex]\( z = 2x + y \)[/tex] at the feasible points.
2. Identify the point which yields the minimum value of [tex]\( z \)[/tex].
### Step 5: Verify and Confirm
After evaluation, the point that minimizes the objective function [tex]\( z = 2x + y \)[/tex] within the feasible region is found to be [tex]\( (x, y) = (0, 8) \)[/tex], and the minimum value of [tex]\( z \)[/tex] at this point is:
[tex]\[ z_{\text{min}} = 2(0) + 8 = 8 \][/tex]
Thus, the minimum value of [tex]\( z \)[/tex] is [tex]\(\boxed{8}\)[/tex].
1. [tex]\( 2y + 3x \geq 16 \)[/tex]
2. [tex]\( 5y + 4x \geq 32 \)[/tex]
3. [tex]\( y + x \geq 7 \)[/tex]
4. [tex]\( x \geq 0 \)[/tex]
5. [tex]\( y \geq 0 \)[/tex]
we follow a systematic approach.
### Step 1: Define the Constraints
First, let's rewrite the inequalities in standard form to understand the feasible region:
- [tex]\( 2y + 3x \geq 16 \)[/tex]
- [tex]\( 5y + 4x \geq 32 \)[/tex]
- [tex]\( y + x \geq 7 \)[/tex]
Additionally, we have non-negativity constraints: [tex]\( x \geq 0 \)[/tex] and [tex]\( y \geq 0 \)[/tex].
### Step 2: Find the Feasible Region
The feasible region is defined by the intersection of the half-planes formed by these inequalities.
### Step 3: Determine Corner Points of the Feasible Region
To minimize the objective function linearly, we need to find the points where the constraint lines intersect. Let's identify some of these points:
1. Intersection of [tex]\( 2y + 3x = 16 \)[/tex] and [tex]\( 5y + 4x = 32 \)[/tex]
2. Intersection of [tex]\( 2y + 3x = 16 \)[/tex] and [tex]\( y + x = 7 \)[/tex]
3. Intersection of [tex]\( 5y + 4x = 32 \)[/tex] and [tex]\( y + x = 7 \)[/tex]
4. Check intersections with the axes, since non-negativity bounds might also be relevant.
### Step 4: Compute the Objective Function
Having identified potential intersection points, we calculate the value of [tex]\( z = 2x + y \)[/tex] for each point and compare them to find the minimum value:
1. Evaluate [tex]\( z = 2x + y \)[/tex] at the feasible points.
2. Identify the point which yields the minimum value of [tex]\( z \)[/tex].
### Step 5: Verify and Confirm
After evaluation, the point that minimizes the objective function [tex]\( z = 2x + y \)[/tex] within the feasible region is found to be [tex]\( (x, y) = (0, 8) \)[/tex], and the minimum value of [tex]\( z \)[/tex] at this point is:
[tex]\[ z_{\text{min}} = 2(0) + 8 = 8 \][/tex]
Thus, the minimum value of [tex]\( z \)[/tex] is [tex]\(\boxed{8}\)[/tex].
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