Find solutions to your problems with the expert advice available on IDNLearn.com. Join our interactive community and access reliable, detailed answers from experienced professionals across a variety of topics.
Sagot :
### Solution:
Let's start by writing the given polynomial expression in standard form and then evaluate it for [tex]\( x = 10 \)[/tex].
#### a. Writing the Expression in Standard Form and Stating the Degree
The given polynomial expression is:
[tex]\[ 3 - 5x^2 + 2 + 8x + x^3 + 7x^2 - 5 \][/tex]
To simplify this expression, we first combine the constant terms and like terms.
#### Step-by-Step Simplification:
1. Combine the constant terms:
[tex]\[ 3 + 2 - 5 = 0 \][/tex]
2. Combine the [tex]\( x^2 \)[/tex] terms:
[tex]\[ -5x^2 + 7x^2 = 2x^2 \][/tex]
3. Combine any remaining terms:
[tex]\[ 8x \][/tex] and [tex]\[ x^3 \][/tex] remain as they are since they do not have like terms.
Putting all these together, the simplified polynomial expression is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
Thus, the polynomial in standard form is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
The degree of a polynomial is the highest power of the variable [tex]\( x \)[/tex]. In this polynomial, the highest power is 3. Therefore, the degree of the polynomial is 3.
#### b. Evaluating the Expression for [tex]\( x = 10 \)[/tex]
Now, we evaluate the polynomial [tex]\( x^3 + 2x^2 + 8x - 5 \)[/tex] for [tex]\( x = 10 \)[/tex].
Substitute [tex]\( x = 10 \)[/tex] into the polynomial:
[tex]\[ (10)^3 + 2(10)^2 + 8(10) - 5 \][/tex]
Calculate each term:
1. [tex]\( (10)^3 = 1000 \)[/tex]
2. [tex]\( 2(10)^2 = 2(100) = 200 \)[/tex]
3. [tex]\( 8(10) = 80 \)[/tex]
4. The constant term remains as [tex]\(-5\)[/tex].
Now, sum these values:
[tex]\[ 1000 + 200 + 80 - 5 \][/tex]
The result is:
[tex]\[ 1275 \][/tex]
Therefore, the evaluated expression for [tex]\( x = 10 \)[/tex] is [tex]\( 1275 \)[/tex].
### Summary:
a. The polynomial in standard form is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
And its degree is: 3
b. The value of the polynomial for [tex]\( x = 10 \)[/tex] is: 1275
Let's start by writing the given polynomial expression in standard form and then evaluate it for [tex]\( x = 10 \)[/tex].
#### a. Writing the Expression in Standard Form and Stating the Degree
The given polynomial expression is:
[tex]\[ 3 - 5x^2 + 2 + 8x + x^3 + 7x^2 - 5 \][/tex]
To simplify this expression, we first combine the constant terms and like terms.
#### Step-by-Step Simplification:
1. Combine the constant terms:
[tex]\[ 3 + 2 - 5 = 0 \][/tex]
2. Combine the [tex]\( x^2 \)[/tex] terms:
[tex]\[ -5x^2 + 7x^2 = 2x^2 \][/tex]
3. Combine any remaining terms:
[tex]\[ 8x \][/tex] and [tex]\[ x^3 \][/tex] remain as they are since they do not have like terms.
Putting all these together, the simplified polynomial expression is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
Thus, the polynomial in standard form is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
The degree of a polynomial is the highest power of the variable [tex]\( x \)[/tex]. In this polynomial, the highest power is 3. Therefore, the degree of the polynomial is 3.
#### b. Evaluating the Expression for [tex]\( x = 10 \)[/tex]
Now, we evaluate the polynomial [tex]\( x^3 + 2x^2 + 8x - 5 \)[/tex] for [tex]\( x = 10 \)[/tex].
Substitute [tex]\( x = 10 \)[/tex] into the polynomial:
[tex]\[ (10)^3 + 2(10)^2 + 8(10) - 5 \][/tex]
Calculate each term:
1. [tex]\( (10)^3 = 1000 \)[/tex]
2. [tex]\( 2(10)^2 = 2(100) = 200 \)[/tex]
3. [tex]\( 8(10) = 80 \)[/tex]
4. The constant term remains as [tex]\(-5\)[/tex].
Now, sum these values:
[tex]\[ 1000 + 200 + 80 - 5 \][/tex]
The result is:
[tex]\[ 1275 \][/tex]
Therefore, the evaluated expression for [tex]\( x = 10 \)[/tex] is [tex]\( 1275 \)[/tex].
### Summary:
a. The polynomial in standard form is:
[tex]\[ x^3 + 2x^2 + 8x - 5 \][/tex]
And its degree is: 3
b. The value of the polynomial for [tex]\( x = 10 \)[/tex] is: 1275
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Find clear answers at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.