To determine which city has the highest population density, we need to compute the population density for each city. Population density is calculated by dividing the population of the city by the area of the city in square miles. Here is the step-by-step solution:
1. Clarkston:
- Population: 44,000
- Area: 33.1 square miles
Population Density:
[tex]\[
\text{Density} = \frac{\text{Population}}{\text{Area}} = \frac{44,000}{33.1} \approx 1329.3051 \, \text{people per square mile}
\][/tex]
2. Westland:
- Population: 29,000
- Area: 23.8 square miles
Population Density:
[tex]\[
\text{Density} = \frac{\text{Population}}{\text{Area}} = \frac{29,000}{23.8} \approx 1218.4874 \, \text{people per square mile}
\][/tex]
3. Eagle Lake:
- Population: 36,000
- Area: 19.7 square miles
Population Density:
[tex]\[
\text{Density} = \frac{\text{Population}}{\text{Area}} = \frac{36,000}{19.7} \approx 1827.4112 \, \text{people per square mile}
\][/tex]
4. Walnut Bay:
- Population: 40,000
- Area: 47.6 square miles
Population Density:
[tex]\[
\text{Density} = \frac{\text{Population}}{\text{Area}} = \frac{40,000}{47.6} \approx 840.3361 \, \text{people per square mile}
\][/tex]
Let's now compare the population densities:
- Clarkston: approximately 1329.3 people per square mile
- Westland: approximately 1218.5 people per square mile
- Eagle Lake: approximately 1827.4 people per square mile
- Walnut Bay: approximately 840.3 people per square mile
From these calculations, we can see that Eagle Lake has the highest population density of approximately 1827.4 people per square mile.
Answer: C. Eagle Lake
