Get detailed and reliable answers to your questions with IDNLearn.com. Discover in-depth answers to your questions from our community of experienced professionals.

Identify the graph of [tex]$f(x) = \frac{10 - 10x^2}{x^2}$[/tex].

Sagot :

To identify the graph of the function [tex]\( f(x) = \frac{10 - 10x^2}{x^2} \)[/tex], we'll proceed through several steps: setting simpler forms, identifying key characteristics, and sketching the behavior. Let's break this down step by step.

### Step 1: Simplify the Function
First, simplify the function to help understand its behavior.

[tex]\[ f(x) = \frac{10 - 10x^2}{x^2} \][/tex]

We can split the expression into two separate fractions:

[tex]\[ f(x) = \frac{10}{x^2} - \frac{10x^2}{x^2} \][/tex]

Simplify further:

[tex]\[ f(x) = \frac{10}{x^2} - 10 \][/tex]

### Step 2: Determine the Domain
Identify the domain of the function. Since [tex]\( x^2 \)[/tex] is in the denominator, [tex]\( x \)[/tex] cannot be zero:

[tex]\[ x \neq 0 \][/tex]

So the domain is all real numbers except zero, or [tex]\( (-\infty, 0) \cup (0, +\infty) \)[/tex].

### Step 3: Analyze Asymptotes
1. Vertical Asymptote:

The function is undefined at [tex]\( x = 0 \)[/tex]. Thus, there is a vertical asymptote at [tex]\( x = 0 \)[/tex].

2. Horizontal Asymptote:

To see if there is a horizontal asymptote, consider the behavior of [tex]\( f(x) \)[/tex] as [tex]\( x \to \pm \infty \)[/tex]:

[tex]\[ \lim_{x \to \pm \infty} f(x) = \lim_{x \to \pm \infty} \left(\frac{10}{x^2} - 10\right) \][/tex]

As [tex]\( x \to \pm \infty \)[/tex], [tex]\( \frac{10}{x^2} \to 0 \)[/tex]:

[tex]\[ \lim_{x \to \pm \infty} f(x) = -10 \][/tex]

Thus, there is a horizontal asymptote at [tex]\( y = -10 \)[/tex].

### Step 4: Analyze Intercepts
1. x-intercepts:

For [tex]\( f(x) \)[/tex] to have x-intercepts, solve [tex]\( f(x) = 0 \)[/tex]:

[tex]\[ \frac{10}{x^2} - 10 = 0 \][/tex]

[tex]\[ \frac{10}{x^2} = 10 \][/tex]

[tex]\[ 10 = 10x^2 \][/tex]

[tex]\[ x^2 = 1 \][/tex]

[tex]\[ x = \pm 1 \][/tex]

Therefore, the x-intercepts are at [tex]\( (-1, 0) \)[/tex] and [tex]\( (1, 0) \)[/tex].

2. y-intercepts:

There is no y-intercept because [tex]\( f(x) \)[/tex] is not defined at [tex]\( x = 0 \)[/tex].

### Step 5: Determine the Behavior of [tex]\( f(x) \)[/tex] Close to Vertical Asymptote
As [tex]\( x \to 0^+ \)[/tex] or [tex]\( x \to 0^- \)[/tex], we need to see how the function behaves:

[tex]\[ f(x) = \frac{10}{x^2} - 10 \][/tex]

- As [tex]\( x \to 0^+ \)[/tex] and [tex]\( x \to 0^- \)[/tex], [tex]\( \frac{10}{x^2} \)[/tex] becomes very large.
- Thus, [tex]\( f(x) \)[/tex] approaches [tex]\( +\infty \)[/tex].

### Step 6: Sketch the Graph

1. Plot vertical asymptote at [tex]\( x = 0 \)[/tex].
2. Identify horizontal asymptote at [tex]\( y = -10 \)[/tex].
3. Locate the x-intercepts at [tex]\( (-1, 0) \)[/tex] and [tex]\( ( 1, 0) \)[/tex].
4. Plot the general behavior:
- As [tex]\( x \)[/tex] approaches 0 from the right and left, [tex]\( f(x) \)[/tex] shoots towards [tex]\( +\infty \)[/tex].
- As [tex]\( x \)[/tex] moves away from the vertical asymptote towards [tex]\(\pm \infty \)[/tex], the function approaches the horizontal asymptote [tex]\( y = -10 \)[/tex].

### Conclusion

Putting all this information together, we can sketch the graph of [tex]\( f(x) \)[/tex]:

- The function will show a steep increase as it approaches [tex]\( x=0 \)[/tex] from either side.
- It will cross the x-axis at [tex]\( x = -1 \)[/tex] and [tex]\( x = 1 \)[/tex].
- Moving away from the center, the curve will asymptotically approach [tex]\( y = -10 \)[/tex].

This is a rational function with characteristics typical of hyperbolic curves with an infinite behavior at the vertical asymptote and flattening out towards the horizontal asymptote.
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.