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Sagot :
Sure! Let's solve this problem step-by-step.
1. Initial Number of Pockets:
You start with a pair of cargo pants that has a total of 6 pockets.
2. Pockets Checked:
You've already checked 2 out of those 6 pockets and did not find the money in either of them.
3. Remaining Pockets:
Since there are 6 pockets in total and you've checked 2, there are [tex]\(6 - 2 = 4\)[/tex] pockets remaining.
4. Finding Probability:
The money must be in one of the remaining 4 pockets. Therefore, the probability that the money will be in the next pocket you check is calculated by taking the reciprocal of the number of remaining pockets.
[tex]\[ \text{Probability} = \frac{1}{\text{number of remaining pockets}} = \frac{1}{4} \][/tex]
Thus, the probability that the money will be in the next pocket you check is [tex]\(\frac{1}{4}\)[/tex].
From the given choices, the correct answer is:
D. [tex]\(\frac{1}{4}\)[/tex]
1. Initial Number of Pockets:
You start with a pair of cargo pants that has a total of 6 pockets.
2. Pockets Checked:
You've already checked 2 out of those 6 pockets and did not find the money in either of them.
3. Remaining Pockets:
Since there are 6 pockets in total and you've checked 2, there are [tex]\(6 - 2 = 4\)[/tex] pockets remaining.
4. Finding Probability:
The money must be in one of the remaining 4 pockets. Therefore, the probability that the money will be in the next pocket you check is calculated by taking the reciprocal of the number of remaining pockets.
[tex]\[ \text{Probability} = \frac{1}{\text{number of remaining pockets}} = \frac{1}{4} \][/tex]
Thus, the probability that the money will be in the next pocket you check is [tex]\(\frac{1}{4}\)[/tex].
From the given choices, the correct answer is:
D. [tex]\(\frac{1}{4}\)[/tex]
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