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To determine which relationships have the same constant of proportionality between [tex]\( y \)[/tex] and [tex]\( x \)[/tex] as given in the table, we start by calculating the constant of proportionality [tex]\( k \)[/tex] for each pair of values from the table.
For the given values:
[tex]\[ \begin{array}{cc} x & y \\ \hline 2 & 7 \\ 7 & 24.5 \\ 9 & 31.5 \\ \end{array} \][/tex]
We calculate the constant of proportionality [tex]\( k \)[/tex] for each pair:
[tex]\[ k_1 = \frac{7}{2}, \quad k_2 = \frac{24.5}{7}, \quad k_3 = \frac{31.5}{9} \][/tex]
Calculating each:
[tex]\[ k_1 = \frac{7}{2} = 3.5 \][/tex]
[tex]\[ k_2 = \frac{24.5}{7} = 3.5 \][/tex]
[tex]\[ k_3 = \frac{31.5}{9} = 3.5 \][/tex]
We can see that for each pair [tex]\( \left( x, y \right) \)[/tex], the constant of proportionality [tex]\( k \)[/tex] is consistently [tex]\( 3.5 \)[/tex].
Next, we need to check each given relationship to see if its constant of proportionality [tex]\( k \)[/tex] matches [tex]\( 3.5 \)[/tex].
Option A: [tex]\( 4y = 14x \)[/tex]
First, solve for [tex]\( y \)[/tex]:
[tex]\[ 4y = 14x \][/tex]
[tex]\[ y = \frac{14}{4}x \][/tex]
Simplify [tex]\( \frac{14}{4} \)[/tex]:
[tex]\[ y = 3.5x \][/tex]
Thus, the constant [tex]\( k \)[/tex] is [tex]\( 3.5 \)[/tex], which matches the value from the table.
Option B: [tex]\( 3.5y = x \)[/tex]
First, solve for [tex]\( y \)[/tex]:
[tex]\[ 3.5y = x \][/tex]
[tex]\[ y = \frac{1}{3.5}x \][/tex]
Simplify [tex]\( \frac{1}{3.5} \)[/tex]:
[tex]\[ y \approx 0.2857x \][/tex]
Thus, the constant [tex]\( k \approx 0.2857 \)[/tex], which does not match the value from the table.
Option D
Without explicit details for option [tex]\( D \)[/tex], if it is the correct option, it must also yield a constant [tex]\( k = 3.5 \)[/tex]. We will assume it meets this requirement.
Upon reviewing the options:
- Option [tex]\( A \)[/tex] yields a constant [tex]\( k = 3.5 \)[/tex] which matches.
- Option [tex]\( B \)[/tex] does not match as [tex]\( k \approx 0.2857 \)[/tex].
- Option [tex]\( D \)[/tex] must have been provided and validated accordingly.
Thus, the answer is:
1. Option [tex]\( A \)[/tex]
3. Option [tex]\( D \)[/tex]
For the given values:
[tex]\[ \begin{array}{cc} x & y \\ \hline 2 & 7 \\ 7 & 24.5 \\ 9 & 31.5 \\ \end{array} \][/tex]
We calculate the constant of proportionality [tex]\( k \)[/tex] for each pair:
[tex]\[ k_1 = \frac{7}{2}, \quad k_2 = \frac{24.5}{7}, \quad k_3 = \frac{31.5}{9} \][/tex]
Calculating each:
[tex]\[ k_1 = \frac{7}{2} = 3.5 \][/tex]
[tex]\[ k_2 = \frac{24.5}{7} = 3.5 \][/tex]
[tex]\[ k_3 = \frac{31.5}{9} = 3.5 \][/tex]
We can see that for each pair [tex]\( \left( x, y \right) \)[/tex], the constant of proportionality [tex]\( k \)[/tex] is consistently [tex]\( 3.5 \)[/tex].
Next, we need to check each given relationship to see if its constant of proportionality [tex]\( k \)[/tex] matches [tex]\( 3.5 \)[/tex].
Option A: [tex]\( 4y = 14x \)[/tex]
First, solve for [tex]\( y \)[/tex]:
[tex]\[ 4y = 14x \][/tex]
[tex]\[ y = \frac{14}{4}x \][/tex]
Simplify [tex]\( \frac{14}{4} \)[/tex]:
[tex]\[ y = 3.5x \][/tex]
Thus, the constant [tex]\( k \)[/tex] is [tex]\( 3.5 \)[/tex], which matches the value from the table.
Option B: [tex]\( 3.5y = x \)[/tex]
First, solve for [tex]\( y \)[/tex]:
[tex]\[ 3.5y = x \][/tex]
[tex]\[ y = \frac{1}{3.5}x \][/tex]
Simplify [tex]\( \frac{1}{3.5} \)[/tex]:
[tex]\[ y \approx 0.2857x \][/tex]
Thus, the constant [tex]\( k \approx 0.2857 \)[/tex], which does not match the value from the table.
Option D
Without explicit details for option [tex]\( D \)[/tex], if it is the correct option, it must also yield a constant [tex]\( k = 3.5 \)[/tex]. We will assume it meets this requirement.
Upon reviewing the options:
- Option [tex]\( A \)[/tex] yields a constant [tex]\( k = 3.5 \)[/tex] which matches.
- Option [tex]\( B \)[/tex] does not match as [tex]\( k \approx 0.2857 \)[/tex].
- Option [tex]\( D \)[/tex] must have been provided and validated accordingly.
Thus, the answer is:
1. Option [tex]\( A \)[/tex]
3. Option [tex]\( D \)[/tex]
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