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Sagot :
Sure! Let's complete Table 2 by filling in the missing values step by step.
Table 1 provided the following data:
- Measured the distance across the anomaly on the map (cm): 0.5 cm, 1.0 cm, 1.5 cm, 3.0 cm
- Scale conversion distance across the anomaly (km): 125 km, 100 km, 75 km, 50 km
- Scale distance across the anomaly converted to cm: 12,500,000 cm (this is the value converted from 125 km), 10,000,000 cm, 7,500,000 cm, 5,000,000 cm (these need to be filled in)
- Total years of Anomaly: 5,000,000 yrs for each anomaly
To find the missing scale distances in cm, we use the conversion rate of 1 km = 100,000 cm.
Let's fill in the missing values for the scale distances in cm:
1. 125 km = 125 100,000 = 12,500,000 cm
2. 100 km = 100 100,000 = 10,000,000 cm
3. 75 km = 75 100,000 = 7,500,000 cm
4. 50 km = 50 100,000 = 5,000,000 cm
Next, we calculate the average seafloor spreading rate (cm/yr) for each anomaly using the formula:
[tex]\[ \text{Average Seafloor Spreading Rate} = \frac{\text{Scale distance across the anomaly in cm}}{\text{Total years of anomaly}} \][/tex]
Given:
- Total years of anomaly = 5,000,000 yrs
Let's calculate:
1. For the first anomaly (12,500,000 cm / 5,000,000 yrs):
[tex]\[ \frac{12,500,000 \text{ cm}}{5,000,000 \text{ yrs}} = 2.5 \text{ cm/yr} \][/tex]
2. For the second anomaly (10,000,000 cm / 5,000,000 yrs):
[tex]\[ \frac{10,000,000 \text{ cm}}{5,000,000 \text{ yrs}} = 2.0 \text{ cm/yr} \][/tex]
3. For the third anomaly (7,500,000 cm / 5,000,000 yrs):
[tex]\[ \frac{7,500,000 \text{ cm}}{5,000,000 \text{ yrs}} = 1.5 \text{ cm/yr} \][/tex]
4. For the fourth anomaly (5,000,000 cm / 5,000,000 yrs):
[tex]\[ \frac{5,000,000 \text{ cm}}{5,000,000 \text{ yrs}} = 1.0 \text{ cm/yr} \][/tex]
Now, let's fill in Table 2:
| | Anomaly I | Anomaly II | Anomaly III | Anomaly IV |
|--------------------------- |----------------|----------------|----------------|------------|
| Measured the distance across anomaly on the map (cm) | 0.5 cm | 1.0 cm | 1.5 cm | 3.0 cm |
| Scale conversion distance across the anomaly (km) | 125 km | 100 km | 75 km | 50 km |
| Scale distance across the anomaly converted to cm | 12,500,000 cm | 10,000,000 cm | 7,500,000 cm | 5,000,000 cm|
| Total years of Anomaly | 5,000,000 yrs | 5,000,000 yrs | 5,000,000 yrs | 5,000,000 yrs|
| Average Seafloor Spreading Rate (cm/yr) of Anomaly| 2.5 cm/yr | 2.0 cm/yr | 1.5 cm/yr | 1.0 cm/yr |
This completes the detailed step-by-step solution for the given measurements and calculations.
Table 1 provided the following data:
- Measured the distance across the anomaly on the map (cm): 0.5 cm, 1.0 cm, 1.5 cm, 3.0 cm
- Scale conversion distance across the anomaly (km): 125 km, 100 km, 75 km, 50 km
- Scale distance across the anomaly converted to cm: 12,500,000 cm (this is the value converted from 125 km), 10,000,000 cm, 7,500,000 cm, 5,000,000 cm (these need to be filled in)
- Total years of Anomaly: 5,000,000 yrs for each anomaly
To find the missing scale distances in cm, we use the conversion rate of 1 km = 100,000 cm.
Let's fill in the missing values for the scale distances in cm:
1. 125 km = 125 100,000 = 12,500,000 cm
2. 100 km = 100 100,000 = 10,000,000 cm
3. 75 km = 75 100,000 = 7,500,000 cm
4. 50 km = 50 100,000 = 5,000,000 cm
Next, we calculate the average seafloor spreading rate (cm/yr) for each anomaly using the formula:
[tex]\[ \text{Average Seafloor Spreading Rate} = \frac{\text{Scale distance across the anomaly in cm}}{\text{Total years of anomaly}} \][/tex]
Given:
- Total years of anomaly = 5,000,000 yrs
Let's calculate:
1. For the first anomaly (12,500,000 cm / 5,000,000 yrs):
[tex]\[ \frac{12,500,000 \text{ cm}}{5,000,000 \text{ yrs}} = 2.5 \text{ cm/yr} \][/tex]
2. For the second anomaly (10,000,000 cm / 5,000,000 yrs):
[tex]\[ \frac{10,000,000 \text{ cm}}{5,000,000 \text{ yrs}} = 2.0 \text{ cm/yr} \][/tex]
3. For the third anomaly (7,500,000 cm / 5,000,000 yrs):
[tex]\[ \frac{7,500,000 \text{ cm}}{5,000,000 \text{ yrs}} = 1.5 \text{ cm/yr} \][/tex]
4. For the fourth anomaly (5,000,000 cm / 5,000,000 yrs):
[tex]\[ \frac{5,000,000 \text{ cm}}{5,000,000 \text{ yrs}} = 1.0 \text{ cm/yr} \][/tex]
Now, let's fill in Table 2:
| | Anomaly I | Anomaly II | Anomaly III | Anomaly IV |
|--------------------------- |----------------|----------------|----------------|------------|
| Measured the distance across anomaly on the map (cm) | 0.5 cm | 1.0 cm | 1.5 cm | 3.0 cm |
| Scale conversion distance across the anomaly (km) | 125 km | 100 km | 75 km | 50 km |
| Scale distance across the anomaly converted to cm | 12,500,000 cm | 10,000,000 cm | 7,500,000 cm | 5,000,000 cm|
| Total years of Anomaly | 5,000,000 yrs | 5,000,000 yrs | 5,000,000 yrs | 5,000,000 yrs|
| Average Seafloor Spreading Rate (cm/yr) of Anomaly| 2.5 cm/yr | 2.0 cm/yr | 1.5 cm/yr | 1.0 cm/yr |
This completes the detailed step-by-step solution for the given measurements and calculations.
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