Find answers to your most challenging questions with the help of IDNLearn.com's experts. Our Q&A platform offers detailed and trustworthy answers to ensure you have the information you need.
Sagot :
To solve this problem, we need to understand the properties of a [tex]\(45^{\circ}-45^{\circ}-90^{\circ}\)[/tex] triangle. In such a triangle, the legs are of equal length and are both denoted as [tex]\(a\)[/tex]. The relationship between the legs and the hypotenuse (denoted as [tex]\(c\)[/tex]) in a [tex]\(45^{\circ}-45^{\circ}-90^{\circ}\)[/tex] triangle is given by:
[tex]\[ c = a \sqrt{2} \][/tex]
Given that the hypotenuse [tex]\( c = 128 \)[/tex] cm, we can find the length of one leg [tex]\( a \)[/tex] by solving the equation:
[tex]\[ 128 = a \sqrt{2} \][/tex]
To isolate [tex]\( a \)[/tex], divide both sides by [tex]\(\sqrt{2}\)[/tex]:
[tex]\[ a = \frac{128}{\sqrt{2}} \][/tex]
To simplify this expression, we multiply the numerator and the denominator by [tex]\(\sqrt{2}\)[/tex]:
[tex]\[ a = \frac{128 \sqrt{2}}{2} \][/tex]
[tex]\[ a = 64 \sqrt{2} \][/tex]
Therefore, the length of one leg of the triangle is:
[tex]\[\boxed{64 \sqrt{2} \, \text{cm}}\][/tex]
[tex]\[ c = a \sqrt{2} \][/tex]
Given that the hypotenuse [tex]\( c = 128 \)[/tex] cm, we can find the length of one leg [tex]\( a \)[/tex] by solving the equation:
[tex]\[ 128 = a \sqrt{2} \][/tex]
To isolate [tex]\( a \)[/tex], divide both sides by [tex]\(\sqrt{2}\)[/tex]:
[tex]\[ a = \frac{128}{\sqrt{2}} \][/tex]
To simplify this expression, we multiply the numerator and the denominator by [tex]\(\sqrt{2}\)[/tex]:
[tex]\[ a = \frac{128 \sqrt{2}}{2} \][/tex]
[tex]\[ a = 64 \sqrt{2} \][/tex]
Therefore, the length of one leg of the triangle is:
[tex]\[\boxed{64 \sqrt{2} \, \text{cm}}\][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your search for solutions ends at IDNLearn.com. Thank you for visiting, and we look forward to helping you again.