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To determine the equation of the quadratic function [tex]\( f(x) \)[/tex] based on the given data points, we will assume the general form of a quadratic equation:
[tex]\[ f(x) = ax^2 + bx + c \][/tex]
Given data points are:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -8 & 13 \\ -7 & 6 \\ -6 & 1 \\ -5 & -2 \\ -4 & -3 \\ -3 & -2 \\ -2 & 1 \\ -1 & 6 \\ 0 & 13 \\ \hline \end{array} \][/tex]
By fitting these points to the quadratic equation, we want to determine the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex].
Through a series of calculations and solving a system of linear equations using methods such as least squares fitting, the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] are found to be:
[tex]\[ a = 1.0000000000000002, \quad b = 8.0, \quad c = 13.000000000000002 \][/tex]
Thus, the quadratic function that fits the given data points is:
[tex]\[ f(x) = 1.0000000000000002 \cdot x^2 + 8.0 \cdot x + 13.000000000000002 \][/tex]
Simplifying the coefficients (since they are very close to whole numbers due to floating point precision), we can approximate the function as:
[tex]\[ f(x) = x^2 + 8x + 13 \][/tex]
This is the equation of the quadratic function [tex]\( f(x) \)[/tex] that fits the provided data points.
[tex]\[ f(x) = ax^2 + bx + c \][/tex]
Given data points are:
[tex]\[ \begin{array}{|c|c|} \hline x & f(x) \\ \hline -8 & 13 \\ -7 & 6 \\ -6 & 1 \\ -5 & -2 \\ -4 & -3 \\ -3 & -2 \\ -2 & 1 \\ -1 & 6 \\ 0 & 13 \\ \hline \end{array} \][/tex]
By fitting these points to the quadratic equation, we want to determine the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex].
Through a series of calculations and solving a system of linear equations using methods such as least squares fitting, the coefficients [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex] are found to be:
[tex]\[ a = 1.0000000000000002, \quad b = 8.0, \quad c = 13.000000000000002 \][/tex]
Thus, the quadratic function that fits the given data points is:
[tex]\[ f(x) = 1.0000000000000002 \cdot x^2 + 8.0 \cdot x + 13.000000000000002 \][/tex]
Simplifying the coefficients (since they are very close to whole numbers due to floating point precision), we can approximate the function as:
[tex]\[ f(x) = x^2 + 8x + 13 \][/tex]
This is the equation of the quadratic function [tex]\( f(x) \)[/tex] that fits the provided data points.
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