Answered

IDNLearn.com makes it easy to find precise answers to your specific questions. Get the information you need from our experts, who provide reliable and detailed answers to all your questions.

How much heat is released when 12.0 grams of helium gas condenses at 2.17 K? The latent heat of vaporization of helium is [tex]$21 J / g$[/tex].

A. [tex]-250 J[/tex]
B. [tex]-26 J[/tex]
C. [tex]26 J[/tex]
D. [tex]250 J[/tex]

Sagot :

GinnyAnsweridn
To determine how much heat is released when 12.0 grams of helium gas condense, we will apply the formula related to latent heat:

[tex]\[ Q = mL \][/tex]

where:
- [tex]\( Q \)[/tex] is the heat released or absorbed during the phase change,
- [tex]\( m \)[/tex] is the mass of the substance,
- [tex]\( L \)[/tex] is the latent heat of vaporization.

Given data:
- The mass of helium ([tex]\( m \)[/tex]) is 12.0 grams.
- The latent heat of vaporization ([tex]\( L \)[/tex]) for helium is [tex]\( 21 \, \text{J/g} \)[/tex].

Step-by-Step Solution:

1. Identify the mass of helium:
[tex]\[ m = 12.0 \, \text{g} \][/tex]

2. Identify the latent heat of vaporization for helium:
[tex]\[ L = 21 \, \text{J/g} \][/tex]

3. Use the formula [tex]\( Q = mL \)[/tex] to calculate the heat released:
[tex]\[ Q = 12.0 \, \text{g} \times 21 \, \text{J/g} \][/tex]

4. Perform the multiplication:
[tex]\[ Q = 252.0 \, \text{J} \][/tex]

Therefore, the heat released when 12.0 grams of helium gas condense at 2.17 K is [tex]\( 252.0 \, \text{J} \)[/tex].

The correct answer among the provided choices is [tex]\( \boxed{250 \text{ J}} \)[/tex].
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.