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Sagot :
Let's solve the given expression step by step.
We need to compute:
[tex]\[ \sqrt{48} - \sqrt{127} - \sqrt{3} \][/tex]
1. Finding [tex]\(\sqrt{48}\)[/tex]:
The square root of 48 is approximately:
[tex]\[ \sqrt{48} \approx 6.928203230275509 \][/tex]
2. Finding [tex]\(\sqrt{127}\)[/tex]:
The square root of 127 is approximately:
[tex]\[ \sqrt{127} \approx 11.269427669584644 \][/tex]
3. Finding [tex]\(\sqrt{3}\)[/tex]:
The square root of 3 is approximately:
[tex]\[ \sqrt{3} \approx 1.7320508075688772 \][/tex]
4. Subtracting the values:
Now, we subtract these values as per the expression:
[tex]\[ 6.928203230275509 - 11.269427669584644 - 1.7320508075688772 \][/tex]
5. Performing the calculations:
[tex]\[ 6.928203230275509 - 11.269427669584644 = -4.341224439309135 \][/tex]
[tex]\[ -4.341224439309135 - 1.7320508075688772 = -6.073275246878012 \][/tex]
Hence, the final result of the expression [tex]\(\sqrt{48} - \sqrt{127} - \sqrt{3}\)[/tex] is approximately:
[tex]\[ -6.073275246878012 \][/tex]
We need to compute:
[tex]\[ \sqrt{48} - \sqrt{127} - \sqrt{3} \][/tex]
1. Finding [tex]\(\sqrt{48}\)[/tex]:
The square root of 48 is approximately:
[tex]\[ \sqrt{48} \approx 6.928203230275509 \][/tex]
2. Finding [tex]\(\sqrt{127}\)[/tex]:
The square root of 127 is approximately:
[tex]\[ \sqrt{127} \approx 11.269427669584644 \][/tex]
3. Finding [tex]\(\sqrt{3}\)[/tex]:
The square root of 3 is approximately:
[tex]\[ \sqrt{3} \approx 1.7320508075688772 \][/tex]
4. Subtracting the values:
Now, we subtract these values as per the expression:
[tex]\[ 6.928203230275509 - 11.269427669584644 - 1.7320508075688772 \][/tex]
5. Performing the calculations:
[tex]\[ 6.928203230275509 - 11.269427669584644 = -4.341224439309135 \][/tex]
[tex]\[ -4.341224439309135 - 1.7320508075688772 = -6.073275246878012 \][/tex]
Hence, the final result of the expression [tex]\(\sqrt{48} - \sqrt{127} - \sqrt{3}\)[/tex] is approximately:
[tex]\[ -6.073275246878012 \][/tex]
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