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To determine how much heat is released when 25.0 grams of liquid copper at its freezing point of 1,085°C changes to solid, we can use the concept of latent heat of fusion. The latent heat of fusion is the amount of heat required to convert a unit mass of a substance from liquid to solid without a change in temperature.
Given data:
- Mass of copper, [tex]\( m = 25.0 \)[/tex] grams
- Latent heat of fusion of copper, [tex]\( L_f = 205.0 \)[/tex] J/g
The formula to calculate the heat released during the phase change is:
[tex]\[ Q = m \cdot L_f \][/tex]
Substitute the given values into the formula:
[tex]\[ Q = 25.0 \, \text{g} \times 205.0 \, \text{J/g} \][/tex]
[tex]\[ Q = 5125.0 \, \text{J} \][/tex]
Thus, the heat released when 25.0 grams of liquid copper changes to solid is [tex]\( 5125.0 \)[/tex] Joules. The correct choice from the given options is therefore:
5,130 J
Given data:
- Mass of copper, [tex]\( m = 25.0 \)[/tex] grams
- Latent heat of fusion of copper, [tex]\( L_f = 205.0 \)[/tex] J/g
The formula to calculate the heat released during the phase change is:
[tex]\[ Q = m \cdot L_f \][/tex]
Substitute the given values into the formula:
[tex]\[ Q = 25.0 \, \text{g} \times 205.0 \, \text{J/g} \][/tex]
[tex]\[ Q = 5125.0 \, \text{J} \][/tex]
Thus, the heat released when 25.0 grams of liquid copper changes to solid is [tex]\( 5125.0 \)[/tex] Joules. The correct choice from the given options is therefore:
5,130 J
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