IDNLearn.com provides a seamless experience for finding the answers you need. Discover the information you need from our experienced professionals who provide accurate and reliable answers to all your questions.
Sagot :
To simplify the complex fraction [tex]\(\frac{1 - \frac{1}{y} - \frac{6}{y^2}}{1 - \frac{4}{y} + \frac{3}{y^2}}\)[/tex] using Method II, we will follow these detailed steps:
1. Combine terms to form a single fraction in the numerator and the denominator:
For the numerator [tex]\(1 - \frac{1}{y} - \frac{6}{y^2}\)[/tex]:
[tex]\[ 1 - \frac{1}{y} - \frac{6}{y^2} = \frac{y^2}{y^2} - \frac{y}{y^2} - \frac{6}{y^2} = \frac{y^2 - y - 6}{y^2} \][/tex]
For the denominator [tex]\(1 - \frac{4}{y} + \frac{3}{y^2}\)[/tex]:
[tex]\[ 1 - \frac{4}{y} + \frac{3}{y^2} = \frac{y^2}{y^2} - \frac{4y}{y^2} + \frac{3}{y^2} = \frac{y^2 - 4y + 3}{y^2} \][/tex]
2. Rewrite the complex fraction as a single fraction:
[tex]\[ \frac{\frac{y^2 - y - 6}{y^2}}{\frac{y^2 - 4y + 3}{y^2}} \][/tex]
3. Simplify by multiplying by the reciprocal of the denominator:
[tex]\[ \frac{y^2 - y - 6}{y^2} \div \frac{y^2 - 4y + 3}{y^2} = \frac{y^2 - y - 6}{y^2} \cdot \frac{y^2}{y^2 - 4y + 3} = \frac{y^2 - y - 6}{y^2 - 4y + 3} \][/tex]
4. Factor both the numerator and the denominator:
The numerator [tex]\(y^2 - y - 6\)[/tex] factors into [tex]\((y - 3)(y + 2)\)[/tex]:
[tex]\[ y^2 - y - 6 = (y - 3)(y + 2) \][/tex]
The denominator [tex]\(y^2 - 4y + 3\)[/tex] factors into [tex]\((y - 1)(y - 3)\)[/tex]:
[tex]\[ y^2 - 4y + 3 = (y - 1)(y - 3) \][/tex]
5. Simplify the factored form by canceling common factors:
[tex]\[ \frac{(y - 3)(y + 2)}{(y - 1)(y - 3)} \][/tex]
The term [tex]\((y - 3)\)[/tex] appears in both the numerator and denominator and can be canceled out:
[tex]\[ \frac{(y - 3)(y + 2)}{(y - 1)(y - 3)} = \frac{y + 2}{y - 1} \][/tex]
Thus, the simplified form of the given complex fraction is:
[tex]\[ \frac{y + 2}{y - 1} \][/tex]
1. Combine terms to form a single fraction in the numerator and the denominator:
For the numerator [tex]\(1 - \frac{1}{y} - \frac{6}{y^2}\)[/tex]:
[tex]\[ 1 - \frac{1}{y} - \frac{6}{y^2} = \frac{y^2}{y^2} - \frac{y}{y^2} - \frac{6}{y^2} = \frac{y^2 - y - 6}{y^2} \][/tex]
For the denominator [tex]\(1 - \frac{4}{y} + \frac{3}{y^2}\)[/tex]:
[tex]\[ 1 - \frac{4}{y} + \frac{3}{y^2} = \frac{y^2}{y^2} - \frac{4y}{y^2} + \frac{3}{y^2} = \frac{y^2 - 4y + 3}{y^2} \][/tex]
2. Rewrite the complex fraction as a single fraction:
[tex]\[ \frac{\frac{y^2 - y - 6}{y^2}}{\frac{y^2 - 4y + 3}{y^2}} \][/tex]
3. Simplify by multiplying by the reciprocal of the denominator:
[tex]\[ \frac{y^2 - y - 6}{y^2} \div \frac{y^2 - 4y + 3}{y^2} = \frac{y^2 - y - 6}{y^2} \cdot \frac{y^2}{y^2 - 4y + 3} = \frac{y^2 - y - 6}{y^2 - 4y + 3} \][/tex]
4. Factor both the numerator and the denominator:
The numerator [tex]\(y^2 - y - 6\)[/tex] factors into [tex]\((y - 3)(y + 2)\)[/tex]:
[tex]\[ y^2 - y - 6 = (y - 3)(y + 2) \][/tex]
The denominator [tex]\(y^2 - 4y + 3\)[/tex] factors into [tex]\((y - 1)(y - 3)\)[/tex]:
[tex]\[ y^2 - 4y + 3 = (y - 1)(y - 3) \][/tex]
5. Simplify the factored form by canceling common factors:
[tex]\[ \frac{(y - 3)(y + 2)}{(y - 1)(y - 3)} \][/tex]
The term [tex]\((y - 3)\)[/tex] appears in both the numerator and denominator and can be canceled out:
[tex]\[ \frac{(y - 3)(y + 2)}{(y - 1)(y - 3)} = \frac{y + 2}{y - 1} \][/tex]
Thus, the simplified form of the given complex fraction is:
[tex]\[ \frac{y + 2}{y - 1} \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.