The equation for the combustion of acetylene is:
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
If 38 grams of water are produced, how many grams of carbon dioxide are also produced?

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02-08-2024
Chemistry

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The equation for the combustion of acetylene is:
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
If 38 grams of water are produced, how many grams of carbon dioxide are also produced?

Sagot :

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Amys2025idn Amys2025idn · Answer 1 · 2024-08-02T21:47:16-04:00

Answer:

190g

Explanation:

Pre-Solving

We are given the following equation:

2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O

We want to know how much carbon dioxide (in grams) is produced if 38 grams of water are produced in the equation.

Solving

We can use dimensional analysis to solve this equation:

[tex]38 g H_2O * \frac{1 mol H_2O}{18 g H_2O} * \frac{4 mol CO_2}{2 mol H_2O} * \frac{44 g CO_2}{1 mol CO_2} = 190 g CO_2[/tex] (rounded to two sig figs).

Sagot :

Pre-Solving

Solving

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