Experience the power of community-driven knowledge on IDNLearn.com. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.

How much hydrochloric acid should be reacted with excess oxygen to produce 44.0 g of chlorine gas?
4HCl + O₂ → 2Cl₂ + 2H₂O
A. 78.0 g
B. 45.2 g
C. 26.2 g
D. 73.7 g
E. 75.8 g


Sagot :

Answer:

B. 45.2 g

Explanation:

Pre-Solving

We are given the following chemical reaction:

4HCl + O₂ → 2Cl₂ + 2H₂O

We need to find out how much hydrochloric acid (HCl) should be reacted with oxygen gas (O₂) to produce 44.0g of chlorine gas (Cl₂).

Since the oxygen gas is in excess, this means that the HCl is our limiting reactant. This means that once we run out of HCl, the reaction can't make any more of the products.

Solving

Convert from Cl₂ to HCl using dimensional analysis:

[tex]44.0g * \frac{1 mol Cl_2}{71.0 g} * \frac{4 mol HCl}{2 mol Cl_2} * \frac{36.5 g HCl}{1 mol HCl} = 45.2 g[/tex]

So, our answer is B (rounded to three sig figs).

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions find answers at IDNLearn.com. Thanks for visiting, and come back for more accurate and reliable solutions.