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How much hydrochloric acid should be reacted with excess oxygen to produce 44.0 g of chlorine gas?
4HCl + O₂ → 2Cl₂ + 2H₂O
A. 78.0 g
B. 45.2 g
C. 26.2 g
D. 73.7 g
E. 75.8 g

Sagot :

Amys2025idn

Answer:

B. 45.2 g

Explanation:

Pre-Solving

We are given the following chemical reaction:

4HCl + O₂ → 2Cl₂ + 2H₂O

We need to find out how much hydrochloric acid (HCl) should be reacted with oxygen gas (O₂) to produce 44.0g of chlorine gas (Cl₂).

Since the oxygen gas is in excess, this means that the HCl is our limiting reactant. This means that once we run out of HCl, the reaction can't make any more of the products.

Solving

Convert from Cl₂ to HCl using dimensional analysis:

[tex]44.0g * \frac{1 mol Cl_2}{71.0 g} * \frac{4 mol HCl}{2 mol Cl_2} * \frac{36.5 g HCl}{1 mol HCl} = 45.2 g[/tex]

So, our answer is B (rounded to three sig figs).

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