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Find the equation for the line that passes through the points (8,3) and (-6, -1). Give your answer in point slope form. You do not need to simplify.

Sagot :

Answer:

[tex]y - 3 = \frac{2}{7} ( x - 8)[/tex]

Step-by-step explanation:

Pre-Solving

We are given that a line passes through the points (8, 3) and (-6, -1). We want to write the equation of this line in point-slope form.

Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point.

First, we need to find the slope of the line.

Solving

The equation for finding the slope from two points is [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex], where [tex](x_1 ,y_1)[/tex] and [tex](x_2 ,y_2)[/tex] are points.

We can label the values of the points beforehand:

[tex]x_1 = 8 \\y_1=3\\x_2=-6\\y_2=-1[/tex]

Now, substitute into the equation.

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{-1-3}{-6-8}[/tex]

[tex]m=\frac{-4}{-14}[/tex]

[tex]m=\frac{2}{7}[/tex]

Now, substitute the values given (m and [tex](x_ 1, y_1)[/tex] into the equation in point-slope form):

[tex]y - 3 = \frac{2}{7} ( x - 8)[/tex]