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What value of [tex]x[/tex] makes this equation true?

[tex]\[
\begin{array}{l}
6x + 3 = 45 \\
x = \square
\end{array}
\][/tex]


Sagot :

To find the value of [tex]\( x \)[/tex] that makes the equation [tex]\( 6x + 3 = 45 \)[/tex] true, follow these steps:

1. Isolate the term with [tex]\( x \)[/tex]:
Begin by eliminating the constant term on the left side of the equation. The constant term here is 3. To do this, subtract 3 from both sides of the equation.
[tex]\[ 6x + 3 - 3 = 45 - 3 \][/tex]
Simplifying both sides, we have:
[tex]\[ 6x = 42 \][/tex]

2. Solve for [tex]\( x \)[/tex]:
Now, to isolate [tex]\( x \)[/tex], divide both sides of the equation by the coefficient of [tex]\( x \)[/tex], which is 6.
[tex]\[ \frac{6x}{6} = \frac{42}{6} \][/tex]
Simplifying the right side, we get:
[tex]\[ x = 7 \][/tex]

Therefore, the value of [tex]\( x \)[/tex] that satisfies the equation [tex]\( 6x + 3 = 45 \)[/tex] is:
[tex]\[ x = 7 \][/tex]