To determine which comparison is true regarding the likelihood of having 1 pet and no children versus another scenario, we'll look at the probabilities.
Let's start by calculating the relevant probabilities from the survey data:
1. Probability of having 1 pet and no children:
- The number of households with 1 pet and no children: 53
- The total number of households surveyed: 335
- Probability = 53 / 335 ≈ 0.1582
2. Probability of having 2 pets and have children:
- The number of households with 2 pets and have children: 85
- The total number of households surveyed: 335
- Probability = 85 / 335 ≈ 0.2537
3. Probability of having 3 or more pets and have children:
- The number of households with 3 or more pets and have children: 46
- The total number of households surveyed: 335
- Probability = 46 / 335 ≈ 0.1373
Now, we compare the probability of having 1 pet and no children with the other scenarios:
- Comparing with 2 pets and have children:
- Probability of having 1 pet and no children (0.1582) < Probability of having 2 pets and have children (0.2537)
- Comparing with 3 or more pets and have children:
- Probability of having 1 pet and no children (0.1582) > Probability of having 3 or more pets and have children (0.1373)
Based on these comparisons, the correct completion for the statement is:
A customer is more likely to have 1 pet and no children than they are to have 3 or more pets and have children.
Thus, the completed statement is:
A customer is more likely to have 1 pet and no children than they are to have 3 or more pets and have children.
