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Determine the discriminant for the quadratic equation [tex]0 = -2x^2 + 3[/tex]. Based on the discriminant value, how many real number solutions does the equation have?

Discriminant: [tex]b^2 - 4ac[/tex]

A. 0
B. 1
C. 2
D. 24


Sagot :

To determine the number of real number solutions for the quadratic equation [tex]\(0 = -2x^2 + 3\)[/tex], we need to calculate the discriminant and then use the value of the discriminant to determine the number of solutions. Here are the steps:

1. Identify the coefficients of the quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex]:
For the given equation [tex]\(0 = -2x^2 + 3\)[/tex]:
[tex]\[ a = -2, \quad b = 0, \quad c = 3 \][/tex]

2. Write down the formula for the discriminant:
The discriminant [tex]\(\Delta\)[/tex] of a quadratic equation [tex]\(ax^2 + bx + c = 0\)[/tex] is given by:
[tex]\[ \Delta = b^2 - 4ac \][/tex]

3. Substitute the values of [tex]\(a\)[/tex], [tex]\(b\)[/tex], and [tex]\(c\)[/tex] into the discriminant formula:
[tex]\[ \Delta = 0^2 - 4(-2)(3) \][/tex]

4. Simplify the expression:
[tex]\[ \Delta = 0 - (-24) \][/tex]
[tex]\[ \Delta = 24 \][/tex]

5. Interpret the value of the discriminant:
The value of the discriminant [tex]\(\Delta\)[/tex] determines the number of real solutions as follows:
- If [tex]\(\Delta > 0\)[/tex], there are 2 distinct real solutions.
- If [tex]\(\Delta = 0\)[/tex], there is exactly 1 real solution (a repeated root).
- If [tex]\(\Delta < 0\)[/tex], there are no real solutions (the solutions are complex).

For our equation, [tex]\(\Delta = 24 > 0\)[/tex].

6. Conclusion:
Since the discriminant [tex]\(\Delta = 24\)[/tex] is greater than zero, the quadratic equation [tex]\(0 = -2x^2 + 3\)[/tex] has 2 distinct real solutions.

Therefore, the discriminant for the quadratic equation is 24, and the equation has 2 real number solutions.