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Sagot :
To solve the given system of equations, we will use the method of substitution or elimination. Here are the steps to find the solution:
1. Write Down the Equations:
[tex]\[ \begin{cases} 2x + 3y = 18 & \text{...Equation (1)} \\ 3x + y = 6 & \text{...Equation (2)} \end{cases} \][/tex]
2. Express y in Terms of x from Equation (2):
[tex]\[ 3x + y = 6 \\ y = 6 - 3x \][/tex]
3. Substitute y into Equation (1):
[tex]\[ 2x + 3(6 - 3x) = 18 \\ 2x + 18 - 9x = 18 \\ -7x + 18 = 18 \][/tex]
4. Solve for x:
[tex]\[ -7x = 0 \\ x = 0 \][/tex]
5. Substitute x Back into the Expression for y:
[tex]\[ y = 6 - 3(0) \\ y = 6 \][/tex]
After solving both equations, we find that the solution to the system of equations is:
[tex]\[ (x, y) = (0, 6) \][/tex]
Therefore, the correct answer is:
[tex]\[ (0, 6) \][/tex]
1. Write Down the Equations:
[tex]\[ \begin{cases} 2x + 3y = 18 & \text{...Equation (1)} \\ 3x + y = 6 & \text{...Equation (2)} \end{cases} \][/tex]
2. Express y in Terms of x from Equation (2):
[tex]\[ 3x + y = 6 \\ y = 6 - 3x \][/tex]
3. Substitute y into Equation (1):
[tex]\[ 2x + 3(6 - 3x) = 18 \\ 2x + 18 - 9x = 18 \\ -7x + 18 = 18 \][/tex]
4. Solve for x:
[tex]\[ -7x = 0 \\ x = 0 \][/tex]
5. Substitute x Back into the Expression for y:
[tex]\[ y = 6 - 3(0) \\ y = 6 \][/tex]
After solving both equations, we find that the solution to the system of equations is:
[tex]\[ (x, y) = (0, 6) \][/tex]
Therefore, the correct answer is:
[tex]\[ (0, 6) \][/tex]
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